If \(\sin(x) = \cos(3x - 30^\circ)\), what is the value of x?
30°
Using \(\sin x = \cos(90^\circ - x)\), the equation becomes \(90^\circ - x = 3x - 30^\circ\). Solving, \(120^\circ = 4x\), so \(x = 30^\circ\).
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What is the value of \(\frac{3 \sin 58^{\circ}}{\cos 32^{\circ}}+\frac{3 \sin 42^{\circ}}{\cos 48^{\circ}}\) ?
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