The problem asks us to find the value of the expression $\sin^3\theta + \operatorname{cosec}^3\theta$ given the condition that $\sin \theta + \operatorname{cosec} \theta = \sqrt{5}$. This can be solved efficiently using algebraic identities combined with trigonometric properties.
We are provided with the equation:
$$ \sin \theta + \operatorname{cosec} \theta = \sqrt{5} $$
Our goal is to determine the value of $\sin^3\theta + \operatorname{cosec}^3\theta$.
First, let's recall the fundamental relationship between cosecant and sine:
$$ \operatorname{cosec}\theta = \frac{1}{\sin\theta} $$
Using this, we can find the product of $\sin\theta$ and $\operatorname{cosec}\theta$:
$$ \sin\theta \times \operatorname{cosec}\theta = \sin\theta \times \frac{1}{\sin\theta} $$
Assuming $\sin\theta \neq 0$, this simplifies to:
$$ \sin\theta \times \operatorname{cosec}\theta = 1 $$
We can use the algebraic identity for the sum of cubes, which is $a^3 + b^3 = (a+b)^3 - 3ab(a+b)$.
Let's set $a = \sin\theta$ and $b = \operatorname{cosec}\theta$. Substituting these into the identity gives us:
$$ \sin^3\theta + \operatorname{cosec}^3\theta = (\sin\theta + \operatorname{cosec}\theta)^3 - 3(\sin\theta)(\operatorname{cosec}\theta)(\sin\theta + \operatorname{cosec}\theta) $$
Now, we substitute the values we know into the derived formula:
Substituting these into the equation:
$$ \sin^3\theta + \operatorname{cosec}^3\theta = (\sqrt{5})^3 - 3(1)(\sqrt{5}) $$
Let's evaluate the terms:
Now, perform the subtraction:
$$ \sin^3\theta + \operatorname{cosec}^3\theta = 5\sqrt{5} - 3\sqrt{5} $$
$$ \sin^3\theta + \operatorname{cosec}^3\theta = (5 - 3)\sqrt{5} $$
$$ \sin^3\theta + \operatorname{cosec}^3\theta = 2\sqrt{5} $$
Therefore, the value of the expression $\sin^3\theta + \operatorname{cosec}^3\theta$ is $2\sqrt{5}$.
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