If sin A = x, then what is the value of tan A in terms of x?
x/√(1-x²)
Given \(\sin A = x\), this represents a right triangle where the opposite side is x and the hypotenuse is 1.
Using the Pythagorean theorem, the adjacent side is \(\sqrt{1-x^2}\).
Since \(\tan A = \frac{\text{opposite}}{\text{adjacent}} = \frac{\sin A}{\cos A}\), substituting gives \(\tan A = \frac{x}{\sqrt{1-x^2}}\).
Hence, the answer is x/√(1-x²).
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