Solving Trigonometric Equation for x
The problem requires finding the value of x given the trigonometric equation: $ \sin(3x + 10^{\circ}) = \cos(2x - 5^{\circ}) $
Using Complementary Angle Identity
We use the trigonometric identity relating sine and cosine: $ \sin(\theta) = \cos(90^{\circ} - \theta) $ Applying this to the given equation, let $ \theta = 3x + 10^{\circ} $. Therefore, $ \sin(3x + 10^{\circ}) = \cos(90^{\circ} - (3x + 10^{\circ})) $
Equating Cosine Terms
Now, substitute this back into the original equation: $ \cos(90^{\circ} - (3x + 10^{\circ})) = \cos(2x - 5^{\circ}) $ For the cosine values to be equal, their arguments must be equal (considering the general solution, we take the simplest case): $ 90^{\circ} - (3x + 10^{\circ}) = 2x - 5^{\circ} $
Step-by-Step Calculation for x
- Simplify the left side: $ 90^{\circ} - 3x - 10^{\circ} = 2x - 5^{\circ} $ $ 80^{\circ} - 3x = 2x - 5^{\circ} $
- Rearrange the terms to group x terms and constant terms: $ 80^{\circ} + 5^{\circ} = 2x + 3x $
- Combine like terms: $ 85^{\circ} = 5x $
- Solve for x by dividing both sides by 5: $ x = \frac{85^{\circ}}{5} $ $ x = 17^{\circ} $
Thus, the value of x is $17^{\circ}$.
Similar Questions
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Important Questions from Trigonometry
The given equation can be reduced to
If sin2x = a - b√c, where a and b are natural numbers and c is prime number, then what is the value of a - b + 2c ?
Let θ be a positive angle. If the number of degrees in θ is divided by the number of radians in θ, then an irrational number 180 / π results. If the number of degrees in θ is multiplied by the number of radians in θ, then an irrational number 125π / 9 results. The angle θ must be equal to
What is sin 2α equal to?
If \(\sin θ = \frac{8}{{17}}\) , then find the value of tan θ.
