The area of a triangle can be calculated when two sides and the angle between them are known. The formula used is:
Area $= \frac{1}{2} ab \sin(C)$
Where 'a' and 'b' are the lengths of the two sides, and 'C' is the measure of the included angle.
Area $= \frac{1}{2} \times 8 \text{ cm} \times 10 \text{ cm} \times \sin(120^\circ)$
The sine of $120^\circ$ is a standard trigonometric value:
$\sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2}$
Now, substitute the sine value back into the area calculation:
Area $= \frac{1}{2} \times 8 \times 10 \times \frac{\sqrt{3}}{2}$
Area $= 4 \times 10 \times \frac{\sqrt{3}}{2}$
Area $= 40 \times \frac{\sqrt{3}}{2}$
Area $= 20\sqrt{3} \text{ cm}^2$
The area of the triangle is $20\sqrt{3} \text{ cm}^2$.
The given equation can be reduced to
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