If g is the geometric mean of 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, then which one of the following is correct?
32 < g < 64
Let's find the geometric mean (g) of the given numbers: 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024.
The geometric mean of a set of n positive numbers is the n-th root of their product.
The given sequence is a geometric progression where the first term is 2 and the common ratio is 2. The terms are $2^1, 2^2, 2^3, \dots, 2^{10}$.
There are 10 numbers in the sequence (from $2^1$ to $2^{10}$). So, n = 10.
The geometric mean (g) is given by the formula:
$$g = \sqrt[n]{a_1 \times a_2 \times \dots \times a_n}$$
In this case, n = 10 and the numbers are 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024.
$$g = \sqrt[10]{2 \times 4 \times 8 \times 16 \times 32 \times 64 \times 128 \times 256 \times 512 \times 1024}$$
We can write each number as a power of 2:
$$g = \sqrt[10]{2^1 \times 2^2 \times 2^3 \times 2^4 \times 2^5 \times 2^6 \times 2^7 \times 2^8 \times 2^9 \times 2^{10}}$$
Using the property of exponents ($a^m \times a^n = a^{m+n}$), we can add the powers of 2:
The sum of the exponents is $1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10$.
This is the sum of the first 10 natural numbers, which can be calculated using the formula $\frac{n(n+1)}{2}$ where n=10.
Sum of exponents $= \frac{10(10+1)}{2} = \frac{10 \times 11}{2} = \frac{110}{2} = 55$.
So, the product of the numbers is $2^{55}$.
Now, substitute this back into the geometric mean formula:
$$g = \sqrt[10]{2^{55}}$$
Using the property of roots and exponents ($\sqrt[n]{a^m} = a^{m/n}$):
$$g = 2^{55/10} = 2^{5.5}$$
We need to determine which range this value falls into. We can rewrite $2^{5.5}$ as $2^5 \times 2^{0.5}$.
$$g = 2^5 \times \sqrt{2}$$
We know that $2^5 = 32$.
So, $g = 32 \times \sqrt{2}$.
We know that the value of $\sqrt{2}$ is approximately 1.414.
Let's estimate the value of g:
$$g \approx 32 \times 1.414$$
Calculating the product:
Adding these values: $32 + 12.8 + 0.32 + 0.128 = 45.248$.
So, $g \approx 45.248$.
Now let's compare this value with the given ranges:
Alternatively, consider the range bounds: $32 = 2^5$ and $64 = 2^6$. The geometric mean is $g = 2^{5.5}$. Since $5 < 5.5 < 6$, it follows that $2^5 < 2^{5.5} < 2^6$, which means $32 < g < 64$. This confirms our estimate.
Therefore, the correct range for the geometric mean g is $32 < g < 64$.
| Concept | Value/Formula |
|---|---|
| Given Sequence | 2, 4, 8, ..., 1024 |
| Number of terms (n) | 10 |
| Sequence in powers of 2 | $2^1, 2^2, \dots, 2^{10}$ |
| Product of terms | $2^1 \times 2^2 \times \dots \times 2^{10} = 2^{1+2+\dots+10} = 2^{55}$ |
| Geometric Mean (g) Formula | $g = \sqrt[n]{\text{Product}}$ |
| Calculated Geometric Mean (g) | $g = \sqrt[10]{2^{55}} = 2^{55/10} = 2^{5.5}$ |
| Approximate Value of g | $g = 2^5 \times \sqrt{2} \approx 32 \times 1.414 \approx 45.248$ |
The geometric mean is a type of average that is often used for sets of positive numbers that are interpreted in terms of their products or compounded values, or for data that follows a geometric progression.
For a set of positive numbers (not all equal), the harmonic mean, geometric mean, and arithmetic mean have the following relationship:
Harmonic Mean $\le$ Geometric Mean $\le$ Arithmetic Mean
Let's quickly calculate the arithmetic mean (AM) for the given sequence to compare.
The sequence is 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024.
Sum $= 2 + 4 + \dots + 1024$. This is a geometric series with $a=2$, $r=2$, $n=10$.
Sum $= a \frac{r^n - 1}{r - 1} = 2 \frac{2^{10} - 1}{2 - 1} = 2 \frac{1024 - 1}{1} = 2 \times 1023 = 2046$.
AM $= \frac{\text{Sum}}{\text{n}} = \frac{2046}{10} = 204.6$.
We found the geometric mean $g \approx 45.248$. As expected, $g < AM$ (45.248 < 204.6).
Based on the calculation $g = 2^{5.5} \approx 45.248$, we confirmed that g falls within the range specified by $32 < g < 64$. This is because $32 = 2^5$ and $64 = 2^6$, and $5 < 5.5 < 6$.
| Term | Definition/Formula | Application in this problem |
|---|---|---|
| Geometric Mean (g) | $\sqrt[n]{a_1 \times a_2 \times \dots \times a_n}$ | Calculated for the given sequence of 10 numbers. |
| Geometric Progression | A sequence where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. | The given sequence 2, 4, ..., 1024 is a geometric progression with common ratio 2. |
| Exponent Properties | $a^m \times a^n = a^{m+n}$, $(a^m)^n = a^{mn}$ | Used to simplify the product of terms and the n-th root calculation. |
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