The sum of even numbers from 1 to 40 is:
An even number is any integer that is divisible by 2 without leaving a remainder. In simpler terms, an even number can be expressed in the form \(2n\), where \(n\) is an integer. Examples of even numbers include 2, 4, 6, 8, and so on.
To find the sum of even numbers from 1 to 40, we first need to list all the even numbers within this range. The even numbers start from 2 and go up to 40, including both.
This sequence forms an arithmetic progression (AP) because the difference between consecutive terms is constant. In this case, the common difference \(d\) is \(4 - 2 = 2\).
To calculate the sum of an arithmetic progression, we need to know the number of terms (\(n\)) in the sequence. For the even numbers from 1 to 40, we can find \(n\) in a few ways:
Now that we know the first term (\(a_1 = 2\)), the last term (\(a_n = 40\)), and the number of terms (\(n = 20\)), we can use the sum formula for an arithmetic progression:
The sum \(S_n\) of an arithmetic progression is given by: $$S_n = \frac{n}{2}(a_1 + a_n)$$ Substituting the values:
$$S_{20} = \frac{20}{2}(2 + 40)$$ $$S_{20} = 10(42)$$ $$S_{20} = 420$$Therefore, the sum of even numbers from 1 to 40 is 420.
Based on our detailed calculation using the principles of arithmetic progression, the sum of even numbers from 1 to 40 is 420. This matches one of the provided options, confirming the accuracy of our steps.
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