All Exams Test series for 1 year @ ₹349 only
Question

If \( f: \mathbb{R} \to \mathbb{R} \) is a function given by \( f(x) = \lfloor x \rfloor \) (greatest integer function), then which of the following is/are correct?

  • (a) \( f \) is one-one
  • (b) \( f \) is not onto
  • (c) Range of \( f \) is \( \mathbb{I} \) (set of integers)
  • (d) \( f(2.5) = 2 \)
  • (e) \( f \) is bijective

Choose the correct answer from the options given below:

The correct answer is

B, C, D only

Understanding the Greatest Integer Function

The question asks us to analyze the properties of the greatest integer function, denoted by \( f(x) = \lfloor x \rfloor \). This function takes any real number \( x \) and returns the largest integer that is less than or equal to \( x \).

Let's examine each statement given in the options to determine which ones are correct for the function \( f: \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = \lfloor x \rfloor \).

Analyzing Statement (a): \( f \) is one-one

A function \( f: A \to B \) is one-one (or injective) if for any two distinct elements \( x_1, x_2 \) in the domain \( A \), their images under \( f \) are also distinct, i.e., if \( x_1 \neq x_2 \), then \( f(x_1) \neq f(x_2) \). Equivalently, if \( f(x_1) = f(x_2) \), then \( x_1 = x_2 \).

Let's consider the greatest integer function \( f(x) = \lfloor x \rfloor \). Take two different real numbers, for example, \( x_1 = 2.1 \) and \( x_2 = 2.5 \). These are distinct numbers, \( 2.1 \neq 2.5 \).

  • \( f(2.1) = \lfloor 2.1 \rfloor = 2 \)
  • \( f(2.5) = \lfloor 2.5 \rfloor = 2 \)

Here, \( f(2.1) = f(2.5) = 2 \), even though \( 2.1 \neq 2.5 \). Since different inputs can give the same output, the function \( f \) is not one-one.

Therefore, statement (a) is incorrect.

Analyzing Statement (b): \( f \) is not onto

A function \( f: A \to B \) is onto (or surjective) if for every element \( y \) in the codomain \( B \), there exists at least one element \( x \) in the domain \( A \) such that \( f(x) = y \).

The domain of \( f \) is \( \mathbb{R} \) (all real numbers), and the codomain is also \( \mathbb{R} \) (all real numbers). The output of the greatest integer function \( \lfloor x \rfloor \) is always an integer.

Consider an element \( y \) in the codomain \( \mathbb{R} \) that is not an integer, for example, \( y = 0.5 \). Can we find a real number \( x \) such that \( f(x) = \lfloor x \rfloor = 0.5 \)? No, because the output of the greatest integer function is always an integer. There is no real number \( x \) whose greatest integer less than or equal to it is 0.5.

Since there are elements in the codomain \( \mathbb{R} \) (like 0.5, 1.7, \(\pi\)) that are not in the range of \( f \), the function \( f \) is not onto.

Therefore, statement (b) is correct.

Analyzing Statement (c): Range of \( f \) is \( \mathbb{I} \) (set of integers)

The range of a function is the set of all possible output values. For \( f(x) = \lfloor x \rfloor \), the definition states that the output is the greatest integer less than or equal to \( x \). This means the output value is always an integer.

Can any integer be an output? Yes. For any integer \( n \in \mathbb{Z} \), we can choose \( x = n \). Then \( f(n) = \lfloor n \rfloor = n \). So, every integer is a possible output of the function.

Thus, the set of all possible output values is the set of all integers, which is denoted by \( \mathbb{Z} \) or \( \mathbb{I} \).

Therefore, statement (c) is correct.

Analyzing Statement (d): \( f(2.5) = 2 \)

We need to evaluate the function \( f(x) = \lfloor x \rfloor \) at \( x = 2.5 \). \( f(2.5) = \lfloor 2.5 \rfloor \).

The greatest integer less than or equal to 2.5 is 2.

\( \lfloor 2.5 \rfloor = 2 \).

Therefore, \( f(2.5) = 2 \), and statement (d) is correct.

Analyzing Statement (e): \( f \) is bijective

A function is bijective if it is both one-one and onto. From our analysis above, we found that the greatest integer function \( f(x) = \lfloor x \rfloor \) is neither one-one (statement a is incorrect) nor onto (statement b is correct, meaning it is not onto).

Since \( f \) is not one-one and not onto, it cannot be bijective.

Therefore, statement (e) is incorrect.

Summary of Statement Analysis

Statement Claim Correctness Reason
(a) \( f \) is one-one Incorrect Different inputs (e.g., 2.1, 2.5) can map to the same output (2).
(b) \( f \) is not onto Correct The range (integers) is a proper subset of the codomain (\(\mathbb{R}\)); non-integer real numbers in the codomain have no preimage.
(c) Range of \( f \) is \( \mathbb{I} \) Correct The output \( \lfloor x \rfloor \) is always an integer, and every integer can be obtained as an output.
(d) \( f(2.5) = 2 \) Correct The greatest integer less than or equal to 2.5 is 2.
(e) \( f \) is bijective Incorrect The function is neither one-one nor onto.

Based on our analysis, statements (b), (c), and (d) are correct.

Conclusion

The correct statements about the greatest integer function \( f(x) = \lfloor x \rfloor \) from \( \mathbb{R} \) to \( \mathbb{R} \) are (b) \( f \) is not onto, (c) Range of \( f \) is \( \mathbb{I} \), and (d) \( f(2.5) = 2 \).

This corresponds to option 2, which lists B, C, D only.

Revision Table: Function Properties

Property Definition Greatest Integer Function (\( f(x) = \lfloor x \rfloor \))
One-one (Injective) \( f(x_1) = f(x_2) \implies x_1 = x_2 \) Not one-one (e.g., \( \lfloor 2.1 \rfloor = \lfloor 2.5 \rfloor = 2 \))
Onto (Surjective) For every \( y \) in codomain, there exists \( x \) in domain such that \( f(x) = y \) Not onto (Range is \( \mathbb{Z} \), Codomain is \( \mathbb{R} \); non-integers in \( \mathbb{R} \) have no preimage)
Bijective Both one-one and onto Not bijective
Domain Set of possible input values \( \mathbb{R} \) (Real Numbers)
Codomain Set where output values are expected to lie \( \mathbb{R} \) (Real Numbers)
Range Set of actual output values \( \mathbb{Z} \) or \( \mathbb{I} \) (Integers)

Additional Information: Greatest Integer Function Details

The greatest integer function \( f(x) = \lfloor x \rfloor \) is also known as the floor function. It is a step function because its graph looks like a series of steps.

  • For any integer \( n \), \( \lfloor n \rfloor = n \).
  • For any non-integer \( x \), \( \lfloor x \rfloor < x \).
  • The value of \( \lfloor x \rfloor \) is constant over any interval \( [n, n+1) \) for an integer \( n \). For instance, \( \lfloor x \rfloor = 3 \) for all \( x \) such that \( 3 \le x < 4 \).
  • The function is discontinuous at every integer value.

Understanding the domain, codomain, and range is crucial when analyzing whether a function is one-one or onto. In this case, the codomain is given as \( \mathbb{R} \), while the range is the set of integers \( \mathbb{Z} \). Since the range is a proper subset of the codomain, the function is not onto.

Was this answer helpful?

Similar Questions

  1. Let \( R \) be the relation on \( \mathbb{N} \) (set of natural numbers) defined by \( R = \{(a, b) : a, b \in \mathbb{N} \) and \( b \) is divisible by \( a\} \). Then the relation \( R \) is:

  2. If \( m \) and \( M \) are respectively minimum and maximum values of \( f(x) = |2 - |x|| \), for \( -3 \leq x \leq 3 \), then:

  3. Let \( R \) be an equivalence relation on the set \( A = \{1,2,3,4,5\} \) given by \( R = \{(x,y):2 \) divides \( (x-y) \} \). Then the equivalence class of 3 is:


Important Questions from Relations and Functions

  1. Which one of the following represents the correct feasible region determined by the following constraints of an LPP?

    \( x + y \geq 10, \quad 2x + 2y \leq 25, \quad x \geq 0, \quad y \geq 0 \)

     

  2. If the function \( f: \mathbb{N} \to \mathbb{N} \) is defined as

    \( f(n) = \begin{cases} n - 1, & \text{if } n \text{ is even} \\ n + 1, & \text{if } n \text{ is odd} \end{cases} \)

    then:

    (A) \( f \) is injective

    (B) f is into

    (C) f is surjective

    (D) f is invertible

    Choose the correct answer from the options given below :

  3. Let [x] denote the greatest integer function. Then match List-I with List-II:

    List-IList-II
    (A) |x - 1| + |x - 2|(I) is differentiable everywhere except at x = 0
    (B) x - |x|(II) is continuous everywhere
    (C) x - [x](III) is not differentiable at x = 1
    (D) x |x|(IV) is differentiable at x = 1

    Choose the correct answer from the options given below:

  4. Let \( R \) be the relation on \( \mathbb{N} \) (set of natural numbers) defined by \( R = \{(a, b) : a, b \in \mathbb{N} \) and \( b \) is divisible by \( a\} \). Then the relation \( R \) is:

  5. If \( m \) and \( M \) are respectively minimum and maximum values of \( f(x) = |2 - |x|| \), for \( -3 \leq x \leq 3 \), then:

Need Expert Advice?
Upcoming Exams
GATE
February 06, 2027
Test Series
CUET UG img
CUET
CUET UG 2026 Mock Test Series
963 Tests 9 Tests Free
18766 Attempts
4(786)
English

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App