If \( f: \mathbb{R} \to \mathbb{R} \) is a function given by \( f(x) = \lfloor x \rfloor \) (greatest integer function), then which of the following is/are correct? Choose the correct answer from the options given below:
B, C, D only
The question asks us to analyze the properties of the greatest integer function, denoted by \( f(x) = \lfloor x \rfloor \). This function takes any real number \( x \) and returns the largest integer that is less than or equal to \( x \).
Let's examine each statement given in the options to determine which ones are correct for the function \( f: \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = \lfloor x \rfloor \).
A function \( f: A \to B \) is one-one (or injective) if for any two distinct elements \( x_1, x_2 \) in the domain \( A \), their images under \( f \) are also distinct, i.e., if \( x_1 \neq x_2 \), then \( f(x_1) \neq f(x_2) \). Equivalently, if \( f(x_1) = f(x_2) \), then \( x_1 = x_2 \).
Let's consider the greatest integer function \( f(x) = \lfloor x \rfloor \). Take two different real numbers, for example, \( x_1 = 2.1 \) and \( x_2 = 2.5 \). These are distinct numbers, \( 2.1 \neq 2.5 \).
Here, \( f(2.1) = f(2.5) = 2 \), even though \( 2.1 \neq 2.5 \). Since different inputs can give the same output, the function \( f \) is not one-one.
Therefore, statement (a) is incorrect.
A function \( f: A \to B \) is onto (or surjective) if for every element \( y \) in the codomain \( B \), there exists at least one element \( x \) in the domain \( A \) such that \( f(x) = y \).
The domain of \( f \) is \( \mathbb{R} \) (all real numbers), and the codomain is also \( \mathbb{R} \) (all real numbers). The output of the greatest integer function \( \lfloor x \rfloor \) is always an integer.
Consider an element \( y \) in the codomain \( \mathbb{R} \) that is not an integer, for example, \( y = 0.5 \). Can we find a real number \( x \) such that \( f(x) = \lfloor x \rfloor = 0.5 \)? No, because the output of the greatest integer function is always an integer. There is no real number \( x \) whose greatest integer less than or equal to it is 0.5.
Since there are elements in the codomain \( \mathbb{R} \) (like 0.5, 1.7, \(\pi\)) that are not in the range of \( f \), the function \( f \) is not onto.
Therefore, statement (b) is correct.
The range of a function is the set of all possible output values. For \( f(x) = \lfloor x \rfloor \), the definition states that the output is the greatest integer less than or equal to \( x \). This means the output value is always an integer.
Can any integer be an output? Yes. For any integer \( n \in \mathbb{Z} \), we can choose \( x = n \). Then \( f(n) = \lfloor n \rfloor = n \). So, every integer is a possible output of the function.
Thus, the set of all possible output values is the set of all integers, which is denoted by \( \mathbb{Z} \) or \( \mathbb{I} \).
Therefore, statement (c) is correct.
We need to evaluate the function \( f(x) = \lfloor x \rfloor \) at \( x = 2.5 \). \( f(2.5) = \lfloor 2.5 \rfloor \).
The greatest integer less than or equal to 2.5 is 2.
\( \lfloor 2.5 \rfloor = 2 \).
Therefore, \( f(2.5) = 2 \), and statement (d) is correct.
A function is bijective if it is both one-one and onto. From our analysis above, we found that the greatest integer function \( f(x) = \lfloor x \rfloor \) is neither one-one (statement a is incorrect) nor onto (statement b is correct, meaning it is not onto).
Since \( f \) is not one-one and not onto, it cannot be bijective.
Therefore, statement (e) is incorrect.
| Statement | Claim | Correctness | Reason |
|---|---|---|---|
| (a) | \( f \) is one-one | Incorrect | Different inputs (e.g., 2.1, 2.5) can map to the same output (2). |
| (b) | \( f \) is not onto | Correct | The range (integers) is a proper subset of the codomain (\(\mathbb{R}\)); non-integer real numbers in the codomain have no preimage. |
| (c) | Range of \( f \) is \( \mathbb{I} \) | Correct | The output \( \lfloor x \rfloor \) is always an integer, and every integer can be obtained as an output. |
| (d) | \( f(2.5) = 2 \) | Correct | The greatest integer less than or equal to 2.5 is 2. |
| (e) | \( f \) is bijective | Incorrect | The function is neither one-one nor onto. |
Based on our analysis, statements (b), (c), and (d) are correct.
The correct statements about the greatest integer function \( f(x) = \lfloor x \rfloor \) from \( \mathbb{R} \) to \( \mathbb{R} \) are (b) \( f \) is not onto, (c) Range of \( f \) is \( \mathbb{I} \), and (d) \( f(2.5) = 2 \).
This corresponds to option 2, which lists B, C, D only.
| Property | Definition | Greatest Integer Function (\( f(x) = \lfloor x \rfloor \)) |
|---|---|---|
| One-one (Injective) | \( f(x_1) = f(x_2) \implies x_1 = x_2 \) | Not one-one (e.g., \( \lfloor 2.1 \rfloor = \lfloor 2.5 \rfloor = 2 \)) |
| Onto (Surjective) | For every \( y \) in codomain, there exists \( x \) in domain such that \( f(x) = y \) | Not onto (Range is \( \mathbb{Z} \), Codomain is \( \mathbb{R} \); non-integers in \( \mathbb{R} \) have no preimage) |
| Bijective | Both one-one and onto | Not bijective |
| Domain | Set of possible input values | \( \mathbb{R} \) (Real Numbers) |
| Codomain | Set where output values are expected to lie | \( \mathbb{R} \) (Real Numbers) |
| Range | Set of actual output values | \( \mathbb{Z} \) or \( \mathbb{I} \) (Integers) |
The greatest integer function \( f(x) = \lfloor x \rfloor \) is also known as the floor function. It is a step function because its graph looks like a series of steps.
Understanding the domain, codomain, and range is crucial when analyzing whether a function is one-one or onto. In this case, the codomain is given as \( \mathbb{R} \), while the range is the set of integers \( \mathbb{Z} \). Since the range is a proper subset of the codomain, the function is not onto.
Let \( R \) be the relation on \( \mathbb{N} \) (set of natural numbers) defined by \( R = \{(a, b) : a, b \in \mathbb{N} \) and \( b \) is divisible by \( a\} \). Then the relation \( R \) is:
If \( m \) and \( M \) are respectively minimum and maximum values of \( f(x) = |2 - |x|| \), for \( -3 \leq x \leq 3 \), then:
Let \( R \) be an equivalence relation on the set \( A = \{1,2,3,4,5\} \) given by \( R = \{(x,y):2 \) divides \( (x-y) \} \). Then the equivalence class of 3 is:
Which one of the following represents the correct feasible region determined by the following constraints of an LPP?
\( x + y \geq 10, \quad 2x + 2y \leq 25, \quad x \geq 0, \quad y \geq 0 \)
If the function \( f: \mathbb{N} \to \mathbb{N} \) is defined as
\( f(n) = \begin{cases} n - 1, & \text{if } n \text{ is even} \\ n + 1, & \text{if } n \text{ is odd} \end{cases} \)
then:
(A) \( f \) is injective
(B) f is into
(C) f is surjective
(D) f is invertible
Choose the correct answer from the options given below :
Let [x] denote the greatest integer function. Then match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) |x - 1| + |x - 2| | (I) is differentiable everywhere except at x = 0 |
| (B) x - |x| | (II) is continuous everywhere |
| (C) x - [x] | (III) is not differentiable at x = 1 |
| (D) x |x| | (IV) is differentiable at x = 1 |
Choose the correct answer from the options given below:
Let \( R \) be the relation on \( \mathbb{N} \) (set of natural numbers) defined by \( R = \{(a, b) : a, b \in \mathbb{N} \) and \( b \) is divisible by \( a\} \). Then the relation \( R \) is:
If \( m \) and \( M \) are respectively minimum and maximum values of \( f(x) = |2 - |x|| \), for \( -3 \leq x \leq 3 \), then: