To solve the problem, we begin by analyzing the given condition: \(\cot(A+B)\cdot\cot(A-B) = 1\).
We know the identity for the cotangent of sum and difference:
The condition \(\cot(A+B) \cdot \cot(A-B) = 1\) implies:
\[\frac{\cot A \cdot \cot B - 1}{\cot A + \cot B} \cdot \frac{\cot A \cdot \cot B + 1}{\cot A - \cot B} = 1\]Simplifying, we recognize an identity involving trigonometric functions:
The key identity here is the angle sum property: \(\cot(A+B) = \cot(90^\circ - (A - B)) = \tan(A - B)\), leading us to conclude based on identity:
Thus, for the cotangent functions to satisfy the given equation as equal to 1, the angles satisfy \(A + B = 90^\circ - (A - B)\), implying symmetric condition about \(45^\circ\).
Now focusing on finding \( \cot\left(\frac{2A}{3}\right) \):
If we apply cotangent transformations and given cotangent identities, we infer:
If as per examination, the known angle transformations reduce to well-known simpler trigonometric equivalents like \(A = 60^\circ\) rotations reducing by such factor or immediate dividing for calculation ease, \[ \cot\left(\frac{2A}{3}\right) = \sqrt{3} \]
Therefore, the correct answer is \(\sqrt{3}\).
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