If cosec θ - cot θ = m, then what is cosec θ equal to?
This problem asks us to find the value of \(\text{cosec } \theta\) given a relationship between \(\text{cosec } \theta\) and \(\text{cot } \theta\). We are given the equation:
\(\text{cosec } \theta - \text{cot } \theta = m\)
To solve this, we need to use a fundamental trigonometric identity that relates \(\text{cosec } \theta\) and \(\text{cot } \theta\). The relevant identity is:
\(\text{cosec}^2 \theta - \text{cot}^2 \theta = 1\)
This identity is in the form of a difference of squares, \(a^2 - b^2 = (a-b)(a+b)\). Applying this to the identity, we get:
\((\text{cosec } \theta - \text{cot } \theta)(\text{cosec } \theta + \text{cot } \theta) = 1\)
We are given that \(\text{cosec } \theta - \text{cot } \theta = m\). We can substitute this value into the factored identity:
\(m (\text{cosec } \theta + \text{cot } \theta) = 1\)
Now, we can solve for the sum \(\text{cosec } \theta + \text{cot } \theta\):
\(\text{cosec } \theta + \text{cot } \theta = \frac{1}{m}\)
Now we have a system of two simple linear equations involving \(\text{cosec } \theta\) and \(\text{cot } \theta\):
To find \(\text{cosec } \theta\), we can add these two equations together. Notice that the \(\text{cot } \theta\) terms will cancel out:
\((\text{cosec } \theta - \text{cot } \theta) + (\text{cosec } \theta + \text{cot } \theta) = m + \frac{1}{m}\)
Combining like terms:
\(2 \text{cosec } \theta = m + \frac{1}{m}\)
Finally, to find \(\text{cosec } \theta\), we divide both sides by 2:
\(\text{cosec } \theta = \frac{1}{2} \left(m + \frac{1}{m}\right)\)
Distributing the \(\frac{1}{2}\) gives:
\(\text{cosec } \theta = \frac{m}{2} + \frac{1}{2m}\)
This expression gives \(\text{cosec } \theta\) in terms of \(m\). We can compare this result with the given options.
The calculated value \(\frac{m}{2} + \frac{1}{2m}\) matches one of the options provided.
Understanding fundamental trigonometric identities is essential for solving problems like this one. Here's a table of some important identities:
| Identity Type | Identity |
|---|---|
| Pythagorean Identity | \(\sin^2 \theta + \cos^2 \theta = 1\) |
| Pythagorean Identity | \(1 + \tan^2 \theta = \sec^2 \theta\) |
| Pythagorean Identity | \(1 + \cot^2 \theta = \text{cosec}^2 \theta\) |
| Reciprocal Identity | \(\text{cosec } \theta = \frac{1}{\sin \theta}\) |
| Reciprocal Identity | \(\sec \theta = \frac{1}{\cos \theta}\) |
| Reciprocal Identity | \(\cot \theta = \frac{1}{\tan \theta}\) |
| Quotient Identity | \(\tan \theta = \frac{\sin \theta}{\cos \theta}\) |
| Quotient Identity | \(\cot \theta = \frac{\cos \theta}{\sin \theta}\) |
The identity \(\text{cosec}^2 \theta - \text{cot}^2 \theta = 1\) used in this problem is a rearrangement of the identity \(1 + \cot^2 \theta = \text{cosec}^2 \theta\).
The cosecant (\(\text{cosec } \theta\)) and cotangent (\(\text{cot } \theta\)) functions are reciprocal functions related to sine (\(\sin \theta\)) and tangent (\(\tan \theta\)), respectively. Specifically:
Problems involving \(\text{cosec } \theta\) and \(\text{cot } \theta\) often utilize the identity \(\text{cosec}^2 \theta - \text{cot}^2 \theta = 1\). Recognizing this identity as a difference of squares is a common technique to derive useful relationships, as demonstrated in this solution.
When you are given an equation like \(\text{cosec } \theta - \text{cot } \theta = m\), and you know the identity \(\text{cosec}^2 \theta - \text{cot}^2 \theta = 1\), you can often find a second relationship, \(\text{cosec } \theta + \text{cot } \theta = \frac{1}{m}\), by using the difference of squares factorization. This technique is very powerful for solving such problems.
Once you have the two linear equations:
You can solve for either \(\text{cosec } \theta\) or \(\text{cot } \theta\) by adding or subtracting the equations. Adding them eliminates \(\text{cot } \theta\) and subtracting the first from the second eliminates \(\text{cosec } \theta\).
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