To solve the given problem, we should start by analyzing the trigonometric equation and finding the required angle.
Hence, the correct answer is \frac{1}{2}.
Evaluate. $(\frac{\sin 23^\circ \cos 67^\circ+\cos 23^\circ \sin 67^\circ}{\text{cosec}^2 15^\circ- \tan^2 75^\circ})^3$
Evaluate the following.
$$\frac{5\cos^2 120^\circ + 4\sec^2 30^\circ - \tan^2 135^\circ} {\sin^2 30^\circ + \cos^2 30^\circ}$$
(secθ + tanθ)/(secθ - tanθ) is equal to:
If tan 45°, cot θ then the value of θ, in radians is
ABC is a triangle If sin (A+B)/2 = √3/2, then the value of sin C/2 is
The angles of elevation of the top of a temple, from the foot and the top of a building 30 m high, are 60° and 30° respectively. Then height of the temple is
The value of sin θ and cos θ when the angle θ is 0 ≤ θ ≤ 90°, is ______