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Question

If $\cos 2\theta = 0$, where $\theta$ is an acute angle, then find the value of $\sin (75^\circ - \theta)$.

This question was previously asked in
SSC Selection Post 2024 Question Paper (26-Jun-2024) (Shift-4)
The correct answer is
$\frac{1}{2}$

To solve the given problem, we should start by analyzing the trigonometric equation and finding the required angle.

  1. Given: \cos 2\theta = 0.
  2. To find the value of \theta satisfying this equation with \theta as an acute angle, we use the property:
    • \cos 2\theta = 0 implies 2\theta = 90^\circ.
    • Therefore, \theta = \frac{90^\circ}{2} = 45^\circ.
  3. Now, we need to find \sin(75^\circ - \theta):
  4. Substitute the value of \theta:
    • \theta = 45^\circ; hence, we need \sin(75^\circ - 45^\circ) = \sin(30^\circ).
  5. Using the known trigonometric value: \sin(30^\circ) = \frac{1}{2}.
  6. Therefore, the value of \sin(75^\circ - \theta) is \frac{1}{2}.

Hence, the correct answer is \frac{1}{2}.

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Similar Questions

  1. If $8 \tan A = 5$, what is the value of $\frac{8\sin A - 7\cos A}{8\sin A + 11\cos A}$?
  2. The expression $sin^2 \theta + cos^2 \theta - 1 = 0$ is satisfied by how many values of $\theta$?
  3. Find the value of (sin $75^\circ$ + sin $15^\circ$).

Important Questions from Trigonometry

  1. The value of 5 sin 14° sec 76° + 3 cot 15° cot 75° + 2 tan 45° is:

  2. If two complimentary angles are in the ratio of 4 : 5, find the greater angle.

  3. If \(\frac{\sin\spaceθ \space+\space \cos\spaceθ} {\sin \spaceθ \space-\space \cos \spaceθ} = \frac{\sqrt3 \space-\space 1}{\sqrt3 \space+\space 1} \) , then the angle θ is 

  4. If tan α = 1/2, tan β = 1/3, then find α + β.

  5. Simplify: sin (A + B) sin (A – B)

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