This question involves calculating the change in kinetic energy when both the mass and speed of an object are altered.
The formula for kinetic energy (KE) is given by:
\(KE = \frac{1}{2}mv^2\)
Where:
Let the initial mass be \(m_1\) and the initial speed be \(v_1\). The initial kinetic energy (\(KE_1\)) is:
\(KE_1 = \frac{1}{2}m_1v_1^2\)
The problem states that both the mass and speed are doubled. So, the new mass (\(m_2\)) and new speed (\(v_2\)) are:
The new kinetic energy (\(KE_2\)) is calculated using the formula with the new values:
\(KE_2 = \frac{1}{2}m_2v_2^2\)
Substitute the values of \(m_2\) and \(v_2\):
\(KE_2 = \frac{1}{2}(2m_1)(2v_1)^2\)
Simplify the expression:
\(KE_2 = \frac{1}{2}(2m_1)(4v_1^2)\)
\(KE_2 = \frac{1}{2}(8m_1v_1^2)\)
Now, relate the new kinetic energy (\(KE_2\)) to the original kinetic energy (\(KE_1\)):
\(KE_2 = 8 \times \left(\frac{1}{2}m_1v_1^2\right)\)
Since \(KE_1 = \frac{1}{2}m_1v_1^2\), we can substitute \(KE_1\) into the equation:
\(KE_2 = 8 \times KE_1\)
Therefore, when both the mass and speed of a ball are doubled, its kinetic energy becomes 8 times its original value.
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