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Question

How fast should a cat of mass 15 kg run in order to have a kinetic energy of 120 J?

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

4 m/s

To determine the speed a cat of mass 15 kg should run to attain a kinetic energy of 120 J, we use the kinetic energy formula:

KE = \(\frac{1}{2}mv^2\)

where KE is kinetic energy, \(m\) is mass, and \(v\) is velocity. We need to solve for \(v\).

First, substitute the given values:

120 = \(\frac{1}{2} \times 15 \times v^2\)

Simplify the equation:

120 = 7.5\(v^2\)

Divide both sides by 7.5:

\(v^2 = \frac{120}{7.5}\)

\(v^2 = 16\)

Take the square root of both sides to find \(v\):

\(v = \sqrt{16}\)

\(v = 4 \text{ m/s}\)

Thus, the cat should run at a speed of 4 m/s to have a kinetic energy of 120 J.

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