How fast should a cat of mass 15 kg run in order to have a kinetic energy of 120 J?
4 m/s
To determine the speed a cat of mass 15 kg should run to attain a kinetic energy of 120 J, we use the kinetic energy formula:
KE = \(\frac{1}{2}mv^2\)
where KE is kinetic energy, \(m\) is mass, and \(v\) is velocity. We need to solve for \(v\).
First, substitute the given values:
120 = \(\frac{1}{2} \times 15 \times v^2\)
Simplify the equation:
120 = 7.5\(v^2\)
Divide both sides by 7.5:
\(v^2 = \frac{120}{7.5}\)
\(v^2 = 16\)
Take the square root of both sides to find \(v\):
\(v = \sqrt{16}\)
\(v = 4 \text{ m/s}\)
Thus, the cat should run at a speed of 4 m/s to have a kinetic energy of 120 J.
The energy possessed by an object by virtue of its motion is known as ________.
Which of the following represents an item with kinetic energy?
An object of mass 10 kg is moving with a uniform velocity of 2 m/s. What will be the kinetic energy of the object?
In an experiment, the velocity of a non-relativistic neutron is determined by measuring the time (~50 ns) it takes to travel from the source to the detector kept at a distance L. Assume that the error in the measurement of L is negligibly small. If we want to estimate the kinetic energy T of the neutron to within 5% accuracy, i.e., IδT / T I ≤ 0.05, the maximum permissible error Iδt Iin measuring the time of flight is nearest to
The kinetic energy of the particles of ______ is maximum.
Two metallic blocks having masses in the ratio 2 : 3 are made to slide down a friction less inclined plane starting initially from rest position. When these blocks reach the bottom of the inclined plane, they will have their kinetic energies in the ratio