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Question

In an experiment, the velocity of a non-relativistic neutron is determined by measuring the time (~50 ns) it takes to travel from the source to the detector kept at a distance L. Assume that the error in the measurement of L is negligibly small. If we want to estimate the kinetic energy T of the neutron to within 5% accuracy, i.e.,   IδT / T I ≤ 0.05, the maximum permissible error Iδt Iin measuring the time of flight is nearest to

The correct answer is

1.25 ns

Neutron Time of Flight and Kinetic Energy

In this experiment, we determine the velocity of a non-relativistic neutron by measuring the distance it travels and the time taken. The velocity (v) is given by the distance (L) divided by the time of flight (t):

$$v = \frac{L}{t}$$

The kinetic energy (T) of the neutron is given by the formula:

$$T = \frac{1}{2}mv^2$$

where m is the mass of the neutron. Substituting the expression for velocity into the kinetic energy formula, we get:

$$T = \frac{1}{2}m\left(\frac{L}{t}\right)^2 = \frac{1}{2}m\frac{L^2}{t^2}$$

We are given that the error in the measurement of L is negligibly small. The mass m of the neutron is also a constant. Therefore, the kinetic energy T depends only on the time of flight t.

The relationship is $T \propto t^{-2}$. To find the relationship between the relative error in kinetic energy ($|\delta T/T|$) and the relative error in time of flight ($|\delta t/t|$), we can use error propagation principles. For a function $f(x) = Cx^n$, where C is a constant, the relationship between relative errors is approximately $|\delta f/f| = |n| |\delta x/x|$.

In our case, $T = \frac{1}{2}mL^2 t^{-2}$. Here, $x$ is t, $n$ is -2, and $C = \frac{1}{2}mL^2$ (which is treated as a constant since errors in m and L are negligible). Thus, the relationship between the relative errors is:

$$\left|\frac{\delta T}{T}\right| = |-2|\left|\frac{\delta t}{t}\right|$$
$$\left|\frac{\delta T}{T}\right| = 2\left|\frac{\delta t}{t}\right|$$

Calculating Permissible Time Error

We are given that we want to estimate the kinetic energy T to within 5% accuracy. This means the relative error in kinetic energy should be less than or equal to 0.05:

$$\left|\frac{\delta T}{T}\right| \le 0.05$$

To find the maximum permissible error in measuring the time of flight ($|\delta t|$), we use the equality:

$$\left|\frac{\delta T}{T}\right| = 0.05$$

Substituting this into our error relationship:

$$0.05 = 2\left|\frac{\delta t}{t}\right|$$

We are given that the approximate time of flight is $t \approx 50$ ns. We can now solve for $|\delta t|$:

$$\left|\frac{\delta t}{t}\right| = \frac{0.05}{2} = 0.025$$
$$|\delta t| = 0.025 \times t$$
$$|\delta t| = 0.025 \times 50 \text{ ns}$$
$$|\delta t| = 1.25 \text{ ns}$$

The maximum permissible error $|\delta t|$ in measuring the time of flight is 1.25 ns to achieve the desired 5% accuracy in the kinetic energy estimate.

Comparing this value to the given options, 1.25 ns is the nearest value.

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Important Questions from Kinetic Energy

  1. An object of mass 2000 g possesses 100 J kinetic energy. The object must be moving with a speed of

  2. A swimmer can achieve a speed of $4$ km/h in still water. If the river current flows at $2$ km/h, and the swimmer aims to cross the river landing directly opposite their starting point, what is the magnitude of the swimmer's effective velocity perpendicular to the river flow?
  3. The kinetic energy of the particles of ______ is maximum.

  4. An object of mass 10 kg is moving with a uniform velocity of 2 m/s. What will be the kinetic energy of the object?

  5. A speeding bullet or a running person are examples of system having ________ energy.

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