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Question

If an infinite GP has the first term x and the sum 5, then which one of the following is correct?

This question was previously asked in
NDA I 2018 GAT Previous Year Paper (22-Apr-2018)
The correct answer is

0 < x < 10

Understanding Infinite Geometric Progressions

An infinite geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio (r).

The sum of an infinite geometric progression exists (converges) only if the absolute value of the common ratio is less than 1, i.e., $|r| < 1$ or $-1 < r < 1$.

The formula for the sum (S) of a convergent infinite GP is given by:

\( S = \frac{a}{1-r} \)

where \( a \) is the first term and \( r \) is the common ratio.

Applying the Infinite GP Sum Formula

In this problem, we are given:

  • The first term \( a = x \)
  • The sum of the infinite GP \( S = 5 \)

Using the sum formula, we have:

\( 5 = \frac{x}{1-r} \)

Finding the Common Ratio in Terms of x

We can rearrange the formula to express \( 1-r \) in terms of \( x \):

\( 1-r = \frac{x}{5} \)

Now, we can find the common ratio \( r \):

\( r = 1 - \frac{x}{5} \)

Applying the Convergence Condition

For the infinite GP to have a finite sum, the common ratio \( r \) must satisfy the condition \( -1 < r < 1 \).

Substitute the expression for \( r \) into the inequality:

\( -1 < 1 - \frac{x}{5} < 1 \)

Solving the Inequality for x

We need to solve this compound inequality for \( x \).

First, subtract 1 from all parts of the inequality:

\( -1 - 1 < 1 - \frac{x}{5} - 1 < 1 - 1 \)

\( -2 < - \frac{x}{5} < 0 \)

Next, multiply all parts of the inequality by -5. Remember that when multiplying or dividing an inequality by a negative number, the direction of the inequality signs must be reversed.

\( (-2) \times (-5) > \left( - \frac{x}{5} \right) \times (-5) > 0 \times (-5) \)

\( 10 > x > 0 \)

This inequality can be read as "10 is greater than x, and x is greater than 0", which is the same as:

\( 0 < x < 10 \)

Conclusion

For an infinite GP with first term \( x \) and sum 5 to exist, the value of \( x \) must be between 0 and 10 (exclusive).

Revision Table: Key Concepts

Concept Formula/Condition
Sum of infinite GP (convergent) \( S = \frac{a}{1-r} \)
Condition for convergence \( |r| < 1 \) or \( -1 < r < 1 \)

Additional Information: Convergence of GP

The convergence of a geometric progression is determined solely by its common ratio, \( r \).

  • If \( |r| < 1 \), the terms get progressively smaller, approaching zero. The sum of infinitely many terms converges to a finite value given by \( \frac{a}{1-r} \).
  • If \( |r| \ge 1 \), the terms do not approach zero (or they oscillate without approaching zero). The sum of infinitely many terms diverges, meaning it does not approach a finite value.
  • If \( r = 1 \), all terms are equal to the first term \( a \). The sum goes to infinity if \( a \ne 0 \).
  • If \( r = -1 \), the terms alternate between \( a \) and \( -a \). The sum oscillates between \( a \) and 0 (or \( a \) and \( -a \)), and does not converge.

Understanding the condition \( |r| < 1 \) is crucial for problems involving sums of infinite geometric sequences.

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Similar Questions

  1. The fifth term of an AP of n terms, whose sum is n 2– 2n, is

  2. A person is to count 4500 notes. Let a ndenote the number of notes he counts in the nth minute. If a 1= a 2= a 3= … = a 10 = 150, and a 10 , a 11 , a 12 , … are in AP with the common difference -2, then the time taken by him to count all the notes is

  3. If \({S_n} = nP + \frac{{n\left( {n - 1} \right)Q}}{2}\) , where S ndenotes the sum of the first n terms of an AP, then the common difference is

  4. If the ratio of AM to GM of two positive numbers a and b is 5 : 3 then a : b is equal to

  5. Let x, y, z be positive real numbers such that x, y, z are in GP and tan -1 x, tan -1 y and tan -1 z are in AP. Then which one of the following is correct?

  6. If x 1and x 2are positive quantities, then the condition for the difference between the arithmetic mean and the geometric mean to be greater than 1 is

  7. If y = x + x 2+ x 3+ … up to infinite terms where x < 1, then which one of the following is correct?

  8. What is the sum of all two-digit numbers which when divided by 3 leave 2 as the remainder?

  9. The third term of a GP is 3. What is the product of the first five terms?

  10. If x, 3/2, z are in AP; x, 3, z are in GP; then which one of the following will be in HP?


Important Questions from Sequences and Series

  1. The fifth term of an AP of n terms, whose sum is n 2– 2n, is

  2. A person is to count 4500 notes. Let a ndenote the number of notes he counts in the nth minute. If a 1= a 2= a 3= … = a 10 = 150, and a 10 , a 11 , a 12 , … are in AP with the common difference -2, then the time taken by him to count all the notes is

  3. \(\mathop {\lim }\limits_{n \to \infty } {\left( {1 - \frac{1}{{2n}}} \right)^{n + 1}}\) is equal to
  4. If \({S_n} = nP + \frac{{n\left( {n - 1} \right)Q}}{2}\) , where S ndenotes the sum of the first n terms of an AP, then the common difference is

  5. What is the sum of the first 12 terms of an arithmetic progression if the 3rd term is -13 and the 6th term is -4?

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