If an infinite GP has the first term x and the sum 5, then which one of the following is correct?
0 < x < 10
An infinite geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio (r).
The sum of an infinite geometric progression exists (converges) only if the absolute value of the common ratio is less than 1, i.e., $|r| < 1$ or $-1 < r < 1$.
The formula for the sum (S) of a convergent infinite GP is given by:
\( S = \frac{a}{1-r} \)
where \( a \) is the first term and \( r \) is the common ratio.
In this problem, we are given:
Using the sum formula, we have:
\( 5 = \frac{x}{1-r} \)
We can rearrange the formula to express \( 1-r \) in terms of \( x \):
\( 1-r = \frac{x}{5} \)
Now, we can find the common ratio \( r \):
\( r = 1 - \frac{x}{5} \)
For the infinite GP to have a finite sum, the common ratio \( r \) must satisfy the condition \( -1 < r < 1 \).
Substitute the expression for \( r \) into the inequality:
\( -1 < 1 - \frac{x}{5} < 1 \)
We need to solve this compound inequality for \( x \).
First, subtract 1 from all parts of the inequality:
\( -1 - 1 < 1 - \frac{x}{5} - 1 < 1 - 1 \)
\( -2 < - \frac{x}{5} < 0 \)
Next, multiply all parts of the inequality by -5. Remember that when multiplying or dividing an inequality by a negative number, the direction of the inequality signs must be reversed.
\( (-2) \times (-5) > \left( - \frac{x}{5} \right) \times (-5) > 0 \times (-5) \)
\( 10 > x > 0 \)
This inequality can be read as "10 is greater than x, and x is greater than 0", which is the same as:
\( 0 < x < 10 \)
For an infinite GP with first term \( x \) and sum 5 to exist, the value of \( x \) must be between 0 and 10 (exclusive).
| Concept | Formula/Condition |
|---|---|
| Sum of infinite GP (convergent) | \( S = \frac{a}{1-r} \) |
| Condition for convergence | \( |r| < 1 \) or \( -1 < r < 1 \) |
The convergence of a geometric progression is determined solely by its common ratio, \( r \).
Understanding the condition \( |r| < 1 \) is crucial for problems involving sums of infinite geometric sequences.
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