All Exams Test series for 1 year @ ₹349 only
Question

If an infinite GP has the first term x and the sum 5, then which one of the following is correct?

The correct answer is

0 < x < 10

Understanding Infinite Geometric Progressions

An infinite geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio (r).

The sum of an infinite geometric progression exists (converges) only if the absolute value of the common ratio is less than 1, i.e., $|r| < 1$ or $-1 < r < 1$.

The formula for the sum (S) of a convergent infinite GP is given by:

\( S = \frac{a}{1-r} \)

where \( a \) is the first term and \( r \) is the common ratio.

Applying the Infinite GP Sum Formula

In this problem, we are given:

  • The first term \( a = x \)
  • The sum of the infinite GP \( S = 5 \)

Using the sum formula, we have:

\( 5 = \frac{x}{1-r} \)

Finding the Common Ratio in Terms of x

We can rearrange the formula to express \( 1-r \) in terms of \( x \):

\( 1-r = \frac{x}{5} \)

Now, we can find the common ratio \( r \):

\( r = 1 - \frac{x}{5} \)

Applying the Convergence Condition

For the infinite GP to have a finite sum, the common ratio \( r \) must satisfy the condition \( -1 < r < 1 \).

Substitute the expression for \( r \) into the inequality:

\( -1 < 1 - \frac{x}{5} < 1 \)

Solving the Inequality for x

We need to solve this compound inequality for \( x \).

First, subtract 1 from all parts of the inequality:

\( -1 - 1 < 1 - \frac{x}{5} - 1 < 1 - 1 \)

\( -2 < - \frac{x}{5} < 0 \)

Next, multiply all parts of the inequality by -5. Remember that when multiplying or dividing an inequality by a negative number, the direction of the inequality signs must be reversed.

\( (-2) \times (-5) > \left( - \frac{x}{5} \right) \times (-5) > 0 \times (-5) \)

\( 10 > x > 0 \)

This inequality can be read as "10 is greater than x, and x is greater than 0", which is the same as:

\( 0 < x < 10 \)

Conclusion

For an infinite GP with first term \( x \) and sum 5 to exist, the value of \( x \) must be between 0 and 10 (exclusive).

Revision Table: Key Concepts

Concept Formula/Condition
Sum of infinite GP (convergent) \( S = \frac{a}{1-r} \)
Condition for convergence \( |r| < 1 \) or \( -1 < r < 1 \)

Additional Information: Convergence of GP

The convergence of a geometric progression is determined solely by its common ratio, \( r \).

  • If \( |r| < 1 \), the terms get progressively smaller, approaching zero. The sum of infinitely many terms converges to a finite value given by \( \frac{a}{1-r} \).
  • If \( |r| \ge 1 \), the terms do not approach zero (or they oscillate without approaching zero). The sum of infinitely many terms diverges, meaning it does not approach a finite value.
  • If \( r = 1 \), all terms are equal to the first term \( a \). The sum goes to infinity if \( a \ne 0 \).
  • If \( r = -1 \), the terms alternate between \( a \) and \( -a \). The sum oscillates between \( a \) and 0 (or \( a \) and \( -a \)), and does not converge.

Understanding the condition \( |r| < 1 \) is crucial for problems involving sums of infinite geometric sequences.

Was this answer helpful?

Important Questions from Sequences and Series

  1. If (a + b), 2b, (b + c) are in HP, then which one of the following is correct?

  2. What is the value of ab?

  3. What is the value of xyz?

  4. What is the value of pqr?

  5. Which one of the following is correct?

    x, y and z are

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App