The problem asks us to find the number of diagonals of a regular polygon given that one of its exterior angles measures 40°.
For any regular polygon, the sum of the exterior angles is 360°. If the polygon has n sides, each exterior angle measures $ \frac{360°}{n} $. We are given that the exterior angle is 40°.
Set up the equation:
$ \frac{360°}{n} = 40° $Solve for n:
$ n = \frac{360°}{40°} $ $ n = 9 $Therefore, the regular polygon has 9 sides (it is a nonagon).
The formula for the number of diagonals (D) in a polygon with n sides is:
$ D = \frac{n(n-3)}{2} $Substitute the value of n = 9 into the formula:
$ D = \frac{9(9-3)}{2} $ $ D = \frac{9(6)}{2} $ $ D = \frac{54}{2} $ $ D = 27 $The polygon has 27 diagonals.