If (a3 + b3 + c3 - 3abc) = 405, and (a - b)2 + (b - c)2 + (c -a)2 = 54, find the value of (a + b + c).
15
This problem requires us to find the value of \((a + b + c)\) using the given values for two algebraic expressions involving \(a\), \(b\), and \(c\). We are given:
To solve this problem, we need to recall two important algebraic identities:
\(a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)\)
\((a - b)^2 + (b - c)^2 + (c - a)^2\)
Let's expand this expression:
\((a^2 - 2ab + b^2) + (b^2 - 2bc + c^2) + (c^2 - 2ca + a^2)\)
\(= a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2\)
\(= 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca\)
\(= 2(a^2 + b^2 + c^2 - ab - bc - ca)\)
So, \((a - b)^2 + (b - c)^2 + (c - a)^2 = 2(a^2 + b^2 + c^2 - ab - bc - ca)\).
Notice that the term \((a^2 + b^2 + c^2 - ab - bc - ca)\) appears in both identities. From the second identity, we can write:
\(a^2 + b^2 + c^2 - ab - bc - ca = \frac{1}{2} \left( (a - b)^2 + (b - c)^2 + (c - a)^2 \right)\)
Now, substitute this into the first identity:
\(a^3 + b^3 + c^3 - 3abc = (a + b + c) \times \frac{1}{2} \left( (a - b)^2 + (b - c)^2 + (c - a)^2 \right)\)
We are given the values for both sides of the equation on the right:
Substitute these values into the combined identity:
\(405 = (a + b + c) \times \frac{1}{2} \times 54\)
\(405 = (a + b + c) \times 27\)
To find the value of \((a + b + c)\), divide both sides by 27:
\(a + b + c = \frac{405}{27}\)
Performing the division:
\(405 \div 27 = 15\)
So, the value of \((a + b + c)\) is 15.
The final answer is 15.
| Identity Name | Formula |
|---|---|
| Sum of Cubes Identity | \(a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)\) |
| Sum of Squares of Differences | \((a - b)^2 + (b - c)^2 + (c - a)^2 = 2(a^2 + b^2 + c^2 - ab - bc - ca)\) |
Algebraic identities are equations that are true for all values of the variables involved. They are powerful tools for simplifying expressions, solving equations, and proving other mathematical relationships.
The identity \(a^3 + b^3 + c^3 - 3abc\) is particularly useful and has interesting properties. For instance, if \(a + b + c = 0\), then \(a^3 + b^3 + c^3 = 3abc\).
The expression \((a - b)^2 + (b - c)^2 + (c - a)^2\) represents twice the sum of the squared differences between variables taken pairwise. It is always non-negative, and it is zero if and only if \(a = b = c\).
Understanding and memorizing common algebraic identities significantly helps in solving complex algebraic problems efficiently during exams.
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