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Question

If \( A \) is an acute angle, which of the following is equal to: \[ \frac{\sin A}{1 + \cos A} \, ? \]

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

\( \frac{1 - \cos A}{\sin A} \) 

 

We need to simplify \( \frac{\sin A}{1 + \cos A} \) and check which option it matches.

Step 1: Multiply by the conjugate

To simplify \( \frac{\sin A}{1 + \cos A} \), multiply the numerator and denominator by the conjugate of \( 1 + \cos A \), which is \( 1 - \cos A \):

\[ \frac{\sin A}{1 + \cos A} \times \frac{1 - \cos A}{1 - \cos A} = \frac{\sin A (1 - \cos A)}{(1 + \cos A)(1 - \cos A)}. \]

Step 2: Simplify the denominator

Using the difference of squares formula:

\[ (1 + \cos A)(1 - \cos A) = 1 - \cos^2 A. \]

Since \( \sin^2 A = 1 - \cos^2 A \), the denominator becomes:

\[ \sin^2 A. \]

Thus, the expression is now:

\[ \frac{\sin A (1 - \cos A)}{\sin^2 A}. \]

Step 3: Simplify the numerator

Split the terms:

\[ \frac{\sin A (1 - \cos A)}{\sin^2 A} = \frac{\sin A}{\sin^2 A} \cdot (1 - \cos A). \]

Simplify \( \frac{\sin A}{\sin^2 A} \) as \( \frac{1}{\sin A} \):

\[ \frac{\sin A (1 - \cos A)}{\sin^2 A} = \frac{1 - \cos A}{\sin A}. \]

Step 4: Compare with options

From the given options, the simplified expression matches:

Option 1: \( \frac{1 - \cos A}{\sin A} \)

Final Answer

The correct option is \( \boxed{3} \).

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