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Question

If A is an acute angle, what is the value of the following expression?

\(\frac{1 + \cos A}{1 - \cos A} - 2\cot A \operatorname{cosec} A\)

This question was previously asked in
RRB Group D 2025 Question Paper (18-Aug-2026) (Shift 1)
The correct answer is

\(\operatorname{cosec}^{2} A + \cot^{2} A\)

Given expression:

\(\frac{1 + \cos A}{1 - \cos A} - 2\cot A \operatorname{cosec} A\)

We know that:

\(2\cot A \operatorname{cosec} A = 2 \cdot \frac{\cos A}{\sin A} \cdot \frac{1}{\sin A} = \frac{2\cos A}{\sin^2 A} = \frac{2\cos A}{(1 - \cos A)(1 + \cos A)}\)

Expressing the first term with the common denominator:

\(\frac{1 + \cos A}{1 - \cos A} = \frac{(1 + \cos A)^2}{(1 - \cos A)(1 + \cos A)} = \frac{1 + 2\cos A + \cos^2 A}{\sin^2 A}\)

Subtracting the second term:

\(\frac{1 + 2\cos A + \cos^2 A - 2\cos A}{\sin^2 A} = \frac{1 + \cos^2 A}{\sin^2 A} = \frac{1}{\sin^2 A} + \frac{\cos^2 A}{\sin^2 A} = \operatorname{cosec}^2 A + \cot^2 A\)

Hence, the correct answer is \(\operatorname{cosec}^{2} A + \cot^{2} A\).

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