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If A, B  and C are denoting Mean, Median and Mode of a data and  A ∶ B  = 9  ∶  8  then the ratio of  B  ∶ C  is:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is 4 ∶  3

Understanding Mean, Median, and Mode Ratios

The question asks us to find the ratio of Median to Mode (B : C) given the ratio of Mean to Median (A : B). We are given that A, B, and C represent the Mean, Median, and Mode of a data set, respectively. The ratio A : B is given as 9 : 8.

Relating Mean, Median, and Mode

For a moderately skewed distribution, there is an empirical relationship between the Mean, Median, and Mode. This relationship is often stated as:

$$ \text{Mode} \approx 3 \times \text{Median} - 2 \times \text{Mean} $$

Using the given notations A, B, and C for Mean, Median, and Mode:

$$ C \approx 3B - 2A $$

Calculating the Ratio B : C

We are given the ratio A : B = 9 : 8. This means that $\frac{A}{B} = \frac{9}{8}$.

We can express A and B in terms of a common constant, say 'k'. Let:

  • A = 9k
  • B = 8k

Here, 'k' is a non-zero constant.

Now, substitute these values into the empirical relationship \(C = 3B - 2A\):

$$ C = 3(8k) - 2(9k) $$

Perform the multiplications:

$$ C = 24k - 18k $$

Subtract the terms:

$$ C = 6k $$

So, we have B = 8k and C = 6k.

We need to find the ratio B : C. This is $\frac{B}{C}$.

$$ \frac{B}{C} = \frac{8k}{6k} $$

Cancel out the common factor 'k' (since k is non-zero):

$$ \frac{B}{C} = \frac{8}{6} $$

Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 2:

$$ \frac{B}{C} = \frac{8 \div 2}{6 \div 2} = \frac{4}{3} $$

Thus, the ratio B : C is 4 : 3.

Comparing with Options

Let's compare our calculated ratio B : C = 4 : 3 with the given options:

  • Option 1: 5 : 4
  • Option 2: 8 : 9
  • Option 3: 7 : 6
  • Option 4: 4 : 3

Our calculated ratio matches Option 4.

Summary of Calculation Steps

Step Description Calculation
1 Given Ratio A : B A : B = 9 : 8
2 Express A and B with a constant k A = 9k, B = 8k
3 Use Empirical Relationship C = 3B - 2A C = 3(8k) - 2(9k)
4 Calculate C C = 24k - 18k = 6k
5 Calculate Ratio B : C $$ \frac{B}{C} = \frac{8k}{6k} $$
6 Simplify Ratio $$ \frac{B}{C} = \frac{4}{3} $$

The ratio of B (Median) to C (Mode) is 4 : 3.

Revision Table: Measures of Central Tendency

Measure Definition Calculation Method Use Case
Mean (A) The average value of a dataset. Sum of all values divided by the number of values. Used for symmetrical data; considers every value.
Median (B) The middle value of a dataset when ordered. Middle value for odd N; average of two middle values for even N. Used for skewed data or data with outliers; less affected by extremes.
Mode (C) The value that appears most frequently. Value with the highest frequency in the dataset. Used for categorical data or to find the most common item.

Additional Information: Empirical Relationship

The empirical relationship Mode \(\approx\) 3 Median - 2 Mean is an approximate relationship that holds true for unimodal distributions that are moderately skewed. It's a useful rule of thumb when the exact relationship is unknown or difficult to calculate directly from the data.

Key points about the relationship:

  • It connects the three main measures of central tendency.
  • It's based on observations of many different datasets, not a strict mathematical proof that applies to all distributions.
  • For a perfectly symmetrical distribution (like a normal distribution), Mean = Median = Mode. In this case, the formula holds true: Mean = 3(Mean) - 2(Mean).
  • The formula is particularly helpful in situations where one of the measures is difficult to find directly, but the other two are known.
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