If a 9V battery is connected across three resistors of 3 ohms, 2 ohms, and 1 ohm in series, what is the current flowing through the circuit?
1.5 A
In series, total resistance is the sum of individual resistances: 3+2+1 = 6 ohms, so current by Ohm's law is I = V/R = 9/6 = 1.5 A. Hence, 1.5 A is correct.
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