This problem requires us to determine the ratio of work output between a man and a woman based on information about combined work efforts.
We are given two groups working together:
The core information is that the combined work rate of Group 1 is 6 times that of Group 2. Our objective is to find the ratio representing how much work 1 man does compared to 1 woman in the same time period.
Let's denote:
These variables represent the amount of work each individual completes in one hour.
We can express the total work rate for each group:
According to the problem statement, the work rate of Group 1 is 6 times the work rate of Group 2. This gives us the equation:
$$9m + 6w = 6 \times (m + 2w)$$
To find the ratio $m : w$, we solve the equation algebraically:
$$9m + 6w = 6m + 12w$$
$$9m - 6m = 12w - 6w$$
$$3m = 6w$$
$$\frac{m}{w} = \frac{6}{3}$$
$$\frac{m}{w} = \frac{2}{1}$$
This result indicates that a man's work rate is double that of a woman's.
The ratio of the work done by 1 man to that of 1 woman in a given time is $m : w$, which equals $2 : 1$.
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