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Question

If \(5 \bullet = \ 20\) and \(7 \bullet = \ 28\), then \(9 \bullet = \ ?\)

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
36

To solve the problem, we need to identify the pattern or logic behind the operations with the symbol \(\bullet\) given in the question. Let's analyze the provided relationships:

  1. Given: \(5 \bullet = 20\). We can interpret this as an operation performed on 5 to get 20.
  2. Given: \(7 \bullet = 28\). Similarly, an operation is performed on 7 to obtain 28.

We assume that there is some consistent arithmetic operation being applied. Let's look for possible patterns:

  1. Observe that \(5 \times 4 = 20\). Hence, the operation could be multiplying 5 by 4.
  2. Observe that \(7 \times 4 = 28\). This suggests the operation is to multiply the number by 4 consistently.

Based on the identified pattern, we hypothesize that \(x \bullet = x \times 4\).

Now, apply this rule to find \(9 \bullet\):

  1. Using the rule, \(9 \times 4 = 36\).

Therefore, \(9 \bullet = 36\). Thus, the solution is consistent with the pattern observed, and the correct answer is 36.

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