If 1st January 2017 was Sunday, then what day of the week was on 1st January 2016?
Friday
This question asks us to find the day of the week for a past date (1st January 2016) given the day of the week for a future date (1st January 2017). To solve this, we need to understand how the day of the week shifts over a period of time, which depends on the total number of days in that period.
The day of the week repeats every 7 days. The shift in the day of the week over a period depends on the remainder when the total number of days is divided by 7. This remainder is often called the number of 'odd days'.
We need to identify if the period between 1st January 2016 and 1st January 2017 includes a leap year and calculate the total number of days.
A year is a leap year if it is divisible by 4, except for century years (years divisible by 100) which are leap years only if they are divisible by 400.
The period from 1st January 2016 to 1st January 2017 includes the entire year 2016. Since 2016 was a leap year, the period contains 366 days.
Now we find the number of odd days in the 366 days between 1st January 2016 and 1st January 2017.
Number of odd days = \(366 \pmod{7}\)
\(366 \div 7 = 52\) with a remainder of \(2\).
So, there are 2 odd days in the period from 1st January 2016 to 1st January 2017.
We know that 1st January 2017 was a Sunday. We are moving backward in time from 1st January 2017 to 1st January 2016. For every odd day, the day of the week shifts forward by one day when moving to a future date. Conversely, when moving to a past date, the day of the week shifts backward by one day for every odd day.
Since there are 2 odd days between 1st January 2016 and 1st January 2017, the day on 1st January 2016 was 2 days before Sunday.
Therefore, if 1st January 2017 was Sunday, then 1st January 2016 was Friday.
The calculation steps are:
Based on our calculation, 1st January 2016 was a Friday.
| Date | Given Day |
|---|---|
| 1st January 2017 | Sunday |
| 1st January 2016 | ? |
| Period | Includes Leap Year? | Total Days | Odd Days (\( \pmod{7} \)) | Day Shift (Forward) |
|---|---|---|---|---|
| 1st Jan 2016 to 1st Jan 2017 | Yes (2016) | 366 | 2 | +2 days |
To find the day going backward (from 2017 to 2016), we shift the day backward by the number of odd days:
Sunday \(\rightarrow\) Saturday (\(-1\) day) \(\rightarrow\) Friday (\(-2\) days)
| Concept | Description | Calculation |
|---|---|---|
| Normal Year | 365 days | \(365 = 52 \times 7 + 1\) (1 odd day) |
| Leap Year | 366 days | \(366 = 52 \times 7 + 2\) (2 odd days) |
| Odd Days | Remainder when total days divided by 7 | Total Days \(\pmod{7}\) |
| Forward Shift | Add odd days to the starting day to find the ending day | Starting Day + Odd Days |
| Backward Shift | Subtract odd days from the ending day to find the starting day | Ending Day - Odd Days |
Understanding odd days is fundamental to solving calendar problems quickly. The number of odd days in a given period directly tells you the shift in the day of the week. For example:
When calculating the day for a date before a given date, you count backward the number of odd days. When calculating for a date after a given date, you count forward.
Remember that February in a leap year has 29 days instead of 28, adding the extra day. This extra day contributes to the additional odd day in a leap year.
Calendar problems often involve calculating odd days over centuries, years, months, and individual days. The principles remain the same: find the total number of days and determine the remainder when divided by 7.
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