If 1, ω, ω 2are the cube roots of unity, then the value of (1 + ω) (1 + ω 2) (1 + ω 4) (1 + ω 8) is
1
The question asks for the value of a specific expression involving the cube roots of unity. Let's first recall the key properties of the cube roots of unity. If 1, ω, and ω2 are the cube roots of unity, they satisfy the following fundamental properties:
From the first property, we can derive useful relationships:
The second property, \(\omega^3 = 1\), is crucial for simplifying powers of ω.
The given expression is \((1 + \omega) (1 + \omega^2) (1 + \omega^4) (1 + \omega^8)\). We need to simplify the terms with powers of ω greater than or equal to 3 using the property \(\omega^3 = 1\).
Substituting these simplified terms back into the original expression, we get:
\((1 + \omega) (1 + \omega^2) (1 + \omega) (1 + \omega^2)\)
This expression can be grouped as:
\(((1 + \omega) (1 + \omega^2))^2\)
Now we use the property \(1 + \omega + \omega^2 = 0\) to simplify the factors \((1 + \omega)\) and \((1 + \omega^2)\).
Substitute these into the grouped expression:
\((-\omega^2)(-\omega)\)
Multiplying these terms:
\((-\omega^2)(-\omega) = \omega^2 \cdot \omega = \omega^3\)
So, the expression inside the parenthesis simplifies to \(\omega^3\).
The entire expression is then \((\omega^3)^2\).
Using the property \(\omega^3 = 1\), we substitute 1 for \(\omega^3\):
\((1)^2 = 1\)
Thus, the value of the given expression \((1 + \omega) (1 + \omega^2) (1 + \omega^4) (1 + \omega^8)\) is 1.
| Property | Mathematical Form |
|---|---|
| Sum of roots | \(1 + \omega + \omega^2 = 0\) |
| Product of roots | \(1 \cdot \omega \cdot \omega^2 = \omega^3 = 1\) |
| Higher powers | \(\omega^{3k} = 1\), \(\omega^{3k+1} = \omega\), \(\omega^{3k+2} = \omega^2\) (for integer k) |
The non-real cube roots of unity, ω and ω2, are complex numbers. They can be expressed in terms of the imaginary unit \(i\) and square roots of 3:
Note that \(\omega^2\) is the complex conjugate of \(\omega\).
While these specific values exist, problems involving expressions like the one in the question are typically solved using the algebraic properties \(1 + \omega + \omega^2 = 0\) and \(\omega^3 = 1\), as this avoids complex number arithmetic and simplifies calculations significantly.
Suppose ω 1and ω 2are two distinct cube roots of unity different from 1. Then what is (ω 1– ω 2) 2equal to?
(x 3– 1) can be factorized as
Where ω is one of the cube roots of unity.
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What is \(\sqrt {\frac{{1 + {{\rm{\omega }}^2}}}{{1 + {\rm{\omega }}}}} \) equal to, where ω is the cube root of unity?