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Question

If 1, ω, ω 2are the cube roots of unity, then the value of (1 + ω) (1 + ω 2) (1 + ω 4) (1 + ω 8) is

The correct answer is

1

Understanding Cube Roots of Unity

The question asks for the value of a specific expression involving the cube roots of unity. Let's first recall the key properties of the cube roots of unity. If 1, ω, and ω2 are the cube roots of unity, they satisfy the following fundamental properties:

  • The sum of the cube roots of unity is zero: \(1 + \omega + \omega^2 = 0\)
  • The cube of either non-real cube root is one: \(\omega^3 = 1\)

From the first property, we can derive useful relationships:

  • \(1 + \omega = -\omega^2\)
  • \(1 + \omega^2 = -\omega\)
  • \(\omega + \omega^2 = -1\)

The second property, \(\omega^3 = 1\), is crucial for simplifying powers of ω.

Simplifying the Expression

The given expression is \((1 + \omega) (1 + \omega^2) (1 + \omega^4) (1 + \omega^8)\). We need to simplify the terms with powers of ω greater than or equal to 3 using the property \(\omega^3 = 1\).

  • For the term \(1 + \omega^4\): Since \(\omega^4 = \omega^3 \cdot \omega = 1 \cdot \omega = \omega\), the term becomes \(1 + \omega\).
  • For the term \(1 + \omega^8\): Since \(\omega^8 = \omega^6 \cdot \omega^2 = (\omega^3)^2 \cdot \omega^2 = 1^2 \cdot \omega^2 = \omega^2\), the term becomes \(1 + \omega^2\).

Substituting these simplified terms back into the original expression, we get:

\((1 + \omega) (1 + \omega^2) (1 + \omega) (1 + \omega^2)\)

This expression can be grouped as:

\(((1 + \omega) (1 + \omega^2))^2\)

Evaluating the Simplified Expression

Now we use the property \(1 + \omega + \omega^2 = 0\) to simplify the factors \((1 + \omega)\) and \((1 + \omega^2)\).

  • \(1 + \omega = -\omega^2\)
  • \(1 + \omega^2 = -\omega\)

Substitute these into the grouped expression:

\((-\omega^2)(-\omega)\)

Multiplying these terms:

\((-\omega^2)(-\omega) = \omega^2 \cdot \omega = \omega^3\)

So, the expression inside the parenthesis simplifies to \(\omega^3\).

The entire expression is then \((\omega^3)^2\).

Using the property \(\omega^3 = 1\), we substitute 1 for \(\omega^3\):

\((1)^2 = 1\)

Thus, the value of the given expression \((1 + \omega) (1 + \omega^2) (1 + \omega^4) (1 + \omega^8)\) is 1.

Summary of Steps

  1. Identify the properties of cube roots of unity: \(1 + \omega + \omega^2 = 0\) and \(\omega^3 = 1\).
  2. Simplify higher powers of \(\omega\) in the expression using \(\omega^3 = 1\). \(\omega^4 = \omega\) and \(\omega^8 = \omega^2\).
  3. Rewrite the expression using the simplified terms: \((1 + \omega)(1 + \omega^2)(1 + \omega)(1 + \omega^2) = ((1 + \omega)(1 + \omega^2))^2\).
  4. Use the property \(1 + \omega + \omega^2 = 0\) to substitute \(1 + \omega = -\omega^2\) and \(1 + \omega^2 = -\omega\).
  5. Evaluate the product inside the parenthesis: \((-\omega^2)(-\omega) = \omega^3\).
  6. Evaluate the final expression: \((\omega^3)^2 = (1)^2 = 1\).

Revision Table: Cube Roots of Unity Properties

Property Mathematical Form
Sum of roots \(1 + \omega + \omega^2 = 0\)
Product of roots \(1 \cdot \omega \cdot \omega^2 = \omega^3 = 1\)
Higher powers \(\omega^{3k} = 1\), \(\omega^{3k+1} = \omega\), \(\omega^{3k+2} = \omega^2\) (for integer k)

Additional Information: Non-real Cube Roots

The non-real cube roots of unity, ω and ω2, are complex numbers. They can be expressed in terms of the imaginary unit \(i\) and square roots of 3:

  • \(\omega = e^{i 2\pi/3} = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
  • \(\omega^2 = e^{i 4\pi/3} = -\frac{1}{2} - i\frac{\sqrt{3}}{2}\)

Note that \(\omega^2\) is the complex conjugate of \(\omega\).

While these specific values exist, problems involving expressions like the one in the question are typically solved using the algebraic properties \(1 + \omega + \omega^2 = 0\) and \(\omega^3 = 1\), as this avoids complex number arithmetic and simplifies calculations significantly.

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Important Questions from Roots of Unity

  1. Suppose ω 1and ω 2are two distinct cube roots of unity different from 1. Then what is (ω 1– ω 2) 2equal to?

  2. (x 3– 1) can be factorized as

    Where ω is one of the cube roots of unity.

  3. If \({\rm{z}} = {\left( {\frac{{\sqrt 3 }}{2} + \frac{{\rm{i}}}{2}} \right)^{107}} + {\left( {\frac{{\sqrt 3 }}{2} - \frac{{\rm{i}}}{2}} \right)^{107}}\) , then what is the imaginary part of z equal to?

  4. What is \(\sqrt {\frac{{1 + {{\rm{\omega }}^2}}}{{1 + {\rm{\omega }}}}} \) equal to, where ω is the cube root of unity?

  5. Find the value of $\omega^{10} + \omega^{20} + \omega^{30} + \omega^{40} + \omega^{50}$, where $\omega$ is a complex cube root of unity.
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