If 1, ω, ω 2are the cube roots of unity, then (1 + ω) (1 + ω 2) (1 + ω 3) (1 + ω + ω 2) is equal to
0
The question asks us to evaluate the expression $$(1 + \omega) (1 + \omega^2) (1 + \omega^3) (1 + \omega + \omega^2)$$ where \(1, \omega, \omega^2\) are the cube roots of unity.
The cube roots of unity, \(1, \omega, \omega^2\), have several important properties:
Let's look at each part of the given expression: $$(1 + \omega) (1 + \omega^2) (1 + \omega^3) (1 + \omega + \omega^2)$$
We will evaluate each factor separately using the properties of cube roots of unity.
| Term | Evaluation | Reasoning |
|---|---|---|
| $$(1 + \omega)$$ | $$-\omega^2$$ | Using $$1 + \omega + \omega^2 = 0$$, we get $$1 + \omega = -\omega^2$$. |
| $$(1 + \omega^2)$$ | $$-\omega$$ | Using $$1 + \omega + \omega^2 = 0$$, we get $$1 + \omega^2 = -1 - \omega = -(1 + \omega)$$. Also from $$1 + \omega + \omega^2 = 0$$, we directly get $$1 + \omega^2 = -\omega$$. |
| $$(1 + \omega^3)$$ | $$1 + 1 = 2$$ | Using the property $$\omega^3 = 1$$. |
| $$(1 + \omega + \omega^2)$$ | $$0$$ | Directly from the sum of roots property $$1 + \omega + \omega^2 = 0$$. |
Now we substitute these evaluated values back into the original expression:
$$(1 + \omega) (1 + \omega^2) (1 + \omega^3) (1 + \omega + \omega^2) = (-\omega^2) \cdot (-\omega) \cdot (2) \cdot (0)$$
When any number or expression is multiplied by zero, the result is always zero.
So, the value of the expression is:
$$-\omega^2 \cdot -\omega \cdot 2 \cdot 0 = 0$$
The value of the expression \((1 + \omega) (1 + \omega^2) (1 + \omega^3) (1 + \omega + \omega^2)\) is 0.
| Property | Formula |
|---|---|
| Roots of $$z^3 = 1$$ | $$1, \omega, \omega^2$$ |
| Sum of roots | $$1 + \omega + \omega^2 = 0$$ |
| Product of roots | $$\omega^3 = 1$$ |
| Relation between roots | $$\omega^2 = \frac{1}{\omega}$$, $$\omega = \frac{1}{\omega^2}$$ |
| Powers of $$\omega$$ | $$\omega^n = \omega^{n \pmod 3}$$ |
The cube roots of unity are complex numbers that lie on the unit circle in the complex plane. Their values are:
These roots form an equilateral triangle inscribed in the unit circle centered at the origin. The properties \(1 + \omega + \omega^2 = 0\) and \(\omega^3 = 1\) are fundamental when working with these roots in various mathematical problems.
The common roots of the equations z 3+ 2z 2+ 2z + 1 = 0 and z 2017 + z 2018 + 1 = 0 are
Suppose ω 1and ω 2are two distinct cube roots of unity different from 1. Then what is (ω 1– ω 2) 2equal to?
If 1, ω, ω 2are the cube roots of unity, then the value of (1 + ω) (1 + ω 2) (1 + ω 4) (1 + ω 8) is
What is the square root of i, where \( i = \sqrt { - 1}\) ?
(x 3– 1) can be factorized as
Where ω is one of the cube roots of unity.
If ω is a non-real cube root of 1, then what is the value of \(\left|\frac{1-\omega}{\omega+\omega^2}\right| ?\)
What is ω 100 + ω 200 + ω 300 equal to, where ω is the cube root of unity?
If \({\rm{z}} = {\left( {\frac{{\sqrt 3 }}{2} + \frac{{\rm{i}}}{2}} \right)^{107}} + {\left( {\frac{{\sqrt 3 }}{2} - \frac{{\rm{i}}}{2}} \right)^{107}}\) , then what is the imaginary part of z equal to?
What is \(\sqrt {\frac{{1 + {{\rm{\omega }}^2}}}{{1 + {\rm{\omega }}}}} \) equal to, where ω is the cube root of unity?
The value of \({\left( {\frac{{ - 1 + {\rm{i}}\sqrt 3 }}{2}} \right)^{\rm{n}}} + {\left( {\frac{{ - 1 - {\rm{i}}\sqrt 3 }}{2}} \right)^{\rm{n}}}\) where n is not a multiple of 3 and \({\rm{i}} = \sqrt { - 1}\) , is
If ω is a cube root of unity, then the value of (1 - ω + ω2) (1 + ω - ω2) is
The common roots of the equations z 3+ 2z 2+ 2z + 1 = 0 and z 2017 + z 2018 + 1 = 0 are
Suppose ω 1and ω 2are two distinct cube roots of unity different from 1. Then what is (ω 1– ω 2) 2equal to?
If 1, ω, ω 2are the cube roots of unity, then the value of (1 + ω) (1 + ω 2) (1 + ω 4) (1 + ω 8) is