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Question

Identify the odd option from among the following.

This question was previously asked in
PYST : General Awareness - SSC Stenographer 2024 (Tier-I) (10-Dec-2024) (Shift 2)
The correct answer is
Argon

The odd option among Bromine, Chlorine, Argon, and Fluorine is Argon.

Bromine, Chlorine, and Fluorine are all halogens. Halogens are a group of non-metal elements in the periodic table. They are highly reactive and readily form salts with metals. They are characterized by having seven valence electrons, meaning they need only one more electron to achieve a stable octet. Argon, however, is a noble gas. Noble gases have a full outer electron shell, making them exceptionally unreactive and chemically inert. This fundamental difference in their chemical properties makes Argon the odd one out.

In summary: Bromine, Chlorine, and Fluorine share the common characteristic of being highly reactive halogens with seven valence electrons, while Argon is an inert noble gas with a full valence shell. This distinct difference in reactivity and electron configuration sets Argon apart.

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