HCF of two numbers is 12. Which one of the following can never be their LCM?
80
The problem asks us to identify which number from the given options can never be the Least Common Multiple (LCM) of two numbers, given that their Highest Common Factor (HCF) is 12.
To solve this, we need to recall a fundamental property that connects the HCF and LCM of any two positive integers. The property states that the LCM of two numbers is always divisible by their HCF. In other words, the LCM is always a multiple of the HCF.
Given that the HCF of the two numbers is 12, their LCM must necessarily be a multiple of 12.
We need to check which of the given options is NOT a multiple of 12.
Let's examine each option provided:
| Option | Value | Is it a multiple of 12? | Explanation |
|---|---|---|---|
| 1 | 80 | No | \(80 \div 12\). \(12 \times 6 = 72\) and \(12 \times 7 = 84\). 80 is not exactly divisible by 12. |
| 2 | 60 | Yes | \(60 \div 12 = 5\). 60 is a multiple of 12. |
| 3 | 36 | Yes | \(36 \div 12 = 3\). 36 is a multiple of 12. |
| 4 | 24 | Yes | \(24 \div 12 = 2\). 24 is a multiple of 12. |
Based on our check, options 2, 3, and 4 (60, 36, and 24) are all multiples of 12. This means they could potentially be the LCM of two numbers whose HCF is 12. For example:
However, option 1 (80) is not a multiple of 12.
Since the LCM of any two numbers must be divisible by their HCF, a number that is not a multiple of the HCF cannot be the LCM.
Therefore, 80 can never be the LCM of two numbers whose HCF is 12.
The property that LCM is always a multiple of HCF is key here. Any value proposed as an LCM must satisfy this condition. If it doesn't, that value cannot be the LCM for the given HCF.
| Concept | Definition | Property with LCM |
|---|---|---|
| HCF (Highest Common Factor) | The largest positive integer that divides each of the integers. | LCM is always divisible by HCF. |
| LCM (Least Common Multiple) | The smallest positive integer that is a multiple of both integers. | LCM is always a multiple of HCF. |
For any two positive integers 'a' and 'b', the product of their HCF and LCM is equal to the product of the numbers themselves. That is:
$\( \text{HCF}(a, b) \times \text{LCM}(a, b) = a \times b $\)
This relationship also reinforces why the LCM must be a multiple of the HCF. Since \(a \times b\) is divisible by both \(a\) and \(b\), and HCF is a factor of both \(a\) and \(b\), the LCM (which relates to \(a \times b / \text{HCF}\)) will naturally be a multiple of the HCF.
If (x + k) is the HCF of x 2+ 5x + 6 and x 2+ 8x + 15, then what is the value of k?
A floor of a big hall has dimensions 30 m 60 cm and 23 m 40 cm. It is to be paved with square tiles of same size. What is the minimum number of tiles required ?
LCM of two numbers is 28 times their HCF. The sum of the HCF and the LCM is 1740. If one of there numbers is 240, then what is the other number ?
The Euclidean algorithm is used to calculate the
What is the HCF of 329 - 9 and 338 - 9 ?
The product of two non-zero expressions is (x + y + z) p 3. If their HCF is p 2, then their LCM is
The LCM of two prime numbers p and q is 2231, where p > q. What is the value of p - q ?
Three runners are running in a circular track, and they complete one round in 20, 30 and 35 minutes respectively. When will they next meet at the starting point ?
What is the least perfect square which is divisible by 3, 4, 5, 6 and 7?
If (x - k) is the HCF of x 2+ ax + b and x 2+ cx + d, then what is the value of k?
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?