The question asks for the slope ($m$) of the linear regression plot of $Y$ on $X$ given three data points: $(2, 60)$, $(4, 70)$, and $(6, 90)$.
The formula for the slope ($m$) in linear regression of $Y$ on $X$ is: $m = \frac{n(\sum XY) - (\sum X)(\sum Y)}{n(\sum X^2) - (\sum X)^2}$ where $n$ is the number of data points.
First, let's list the data points and calculate the necessary sums:
| X | Y | $X^2$ | XY | |
|---|---|---|---|---|
| 2 | 60 | 4 | 120 | |
| 4 | 70 | 16 | 280 | |
| 6 | 90 | 36 | 540 | |
| Sum | $\sum X = 12$ | $\sum Y = 220$ | $\sum X^2 = 56$ | $\sum XY = 940$ |
Now, substitute the calculated sums into the slope formula:
$m = \frac{3(940) - (12)(220)}{3(56) - (12)^2}$ $m = \frac{2820 - 2640}{168 - 144}$ $m = \frac{180}{24}$ $m = 7.5$The slope ($m$) of the linear regression plot is $7.5$.
There is no value of x that can simultaneously satisfy both the given equations. Therefore, find the ‘least squares error’ solution to the two equations, i.e., find the value of x that minimizes the sum of squares of the errors in the two equations. __________
2x = 3
4x = 1
| $x$ | 2 | 3 | 4 | 5 |
| $y$ | 8 | 9 | 7 | 16 |
| $x$ | 1 | 2 | 3 | 4 |
| $y$ | 2 | 6 | 7 | 10 |
The graph below shows a plot of annual rainfall on the X axis and number of plant species on the Y axis. Based on the pattern in the graph, which one of the following statistical methods would be most appropriate to model the relationship between annual rainfall and the number of plant species?
