Given that \(\tan\theta = 2\) and \(\theta\) is in the first quadrant, what is the value of \(\sec\theta\)?
\(\sqrt{5}\)
Using the trigonometric identity \(\sec^2\theta = 1 + \tan^2\theta\).
Substituting \(\tan\theta = 2\): \(\sec^2\theta = 1 + 2^2 = 1 + 4 = 5\).
So \(\sec\theta = \sqrt{5}\).
Since \(\theta\) is in the first quadrant, all trigonometric ratios are positive, so the positive root is taken.
Hence, the value of \(\sec\theta\) is \(\sqrt{5}\).
What is the ratio of the greatest to the smallest value of 2 – 2 sin x – sin 2x, 0 ≤ x ≤ (π/2)?
If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ
If x, y are acute angles, where 0 < x + y < 90° and sin(3x - 40°) = cos (3y + 40°), then the value of tan (x + y) is equal to
What is (1 + cot θ - cosec θ)(1 + tan θ + sec θ) equal to?
If \(\sin \theta =\frac{3}{5}\) and \(\cos \theta =\frac{4}{5}\) , then the value of \(\frac{1+\tan \theta}{1-\cot \theta}\) is: