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Question

From the top of a lighthouse, 100 m high, the angle of depression of a boat is \({\tan ^{ - 1}}\left( {\frac{5}{{12}}} \right).\) What is the distance between the boat and the lighthouse?

This question was previously asked in
NDA I 2017 GAT Previous Year Paper (23-Apr-2017)
The correct answer is

240 m

Understanding the Problem: Lighthouse, Boat, and Angle of Depression

The problem asks us to find the distance between a boat and the base of a lighthouse, given the height of the lighthouse and the angle of depression from the top of the lighthouse to the boat.

The angle of depression is the angle between the horizontal line of sight and the line of sight downwards to an object. When looking from the top of the lighthouse down at the boat, this angle is formed.

Relating Angle of Depression and Elevation

In this scenario, the angle of depression from the top of the lighthouse to the boat is equal to the angle of elevation from the boat to the top of the lighthouse. This is because the horizontal line from the top of the lighthouse is parallel to the water surface (where the boat is), and the line of sight acts as a transversal. These angles are alternate interior angles.

Let the angle of depression (and thus the angle of elevation) be \(\theta\). We are given that \(\theta = {\tan ^{ - 1}}\left( {\frac{5}{{12}}} \right)\).

This means that the tangent of the angle \(\theta\) is \(\tan(\theta) = \frac{5}{12}\).

Setting up the Right Triangle

We can visualize this problem as a right-angled triangle. The vertices of the triangle are:

  • The top of the lighthouse.
  • The base of the lighthouse.
  • The position of the boat.

In this right triangle:

  • The height of the lighthouse (100 m) is the side opposite to the angle of elevation (\(\theta\)) from the boat.
  • The distance between the boat and the base of the lighthouse is the side adjacent to the angle of elevation (\(\theta\)) from the boat. This is what we need to find.

Using Trigonometry: The Tangent Ratio

The tangent function in a right-angled triangle relates the opposite side to the adjacent side:

\(\tan(\text{angle}) = \frac{\text{Opposite Side}}{\text{Adjacent Side}}\)

In our case, with the angle of elevation \(\theta\) at the boat:

\(\tan(\theta) = \frac{\text{Height of Lighthouse}}{\text{Distance between boat and lighthouse}}\)

Step-by-Step Calculation

We know that \(\tan(\theta) = \frac{5}{12}\) and the Height of the Lighthouse is 100 m. Let 'd' be the distance between the boat and the lighthouse.

So, we have the equation:

\(\frac{5}{12} = \frac{100}{d}\)

To find 'd', we can cross-multiply:

\(5 \times d = 12 \times 100\)

\(5d = 1200\)

Now, divide by 5 to isolate 'd':

\(d = \frac{1200}{5}\)

\(d = 240\)

So, the distance between the boat and the lighthouse is 240 meters.

Final Answer

The distance between the boat and the lighthouse is 240 m.

Quantity Value
Height of Lighthouse 100 m
Angle of Depression (\(\theta\)) \({\tan ^{ - 1}}\left( {\frac{5}{{12}}} \right)\)
\(\tan(\theta)\) \(\frac{5}{12}\)
Distance (d) ?

Revision Table: Lighthouse Distance Calculation

Concept Explanation Application
Angle of Depression Angle between horizontal line of sight and downward line of sight. Used to determine angle of elevation at the boat.
Trigonometric Ratios Relationships between angles and side lengths in right triangles (SOH CAH TOA). Tangent (TOA): \(\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}\).
Right Triangle Formed by lighthouse height, distance on water, and line of sight. Allows use of trigonometric ratios to solve for unknown side.

Additional Information: Angles of Elevation and Depression

Angles of elevation and depression are crucial concepts in trigonometry, often used in problems involving heights and distances.

  • Angle of Elevation: When you look *up* at an object, the angle between your horizontal line of sight and your line of sight up to the object is the angle of elevation.
  • Angle of Depression: When you look *down* at an object, the angle between your horizontal line of sight and your line of sight down to the object is the angle of depression.

It's important to remember that the horizontal line of sight is always parallel to the ground (assuming the ground is flat). This parallelism is why the angle of depression from point A to point B is equal to the angle of elevation from point B to point A, forming alternate interior angles when the line of sight acts as a transversal.

These concepts are widely applied in surveying, navigation, physics, and engineering to calculate distances and heights indirectly.

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Important Questions from Heights and Distances

  1. A peacock sitting at the top of a 3 meter high pole saw a snake approaching towards pole at a distance three times of the height of the pole. Then it jumping from pole will catch the snake at what distance from the pole if both are running with same speed ?

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