A ladder 9 m long reaches a point 9 m below the top of a vertical flagstaff. From the foot of the ladder, the elevation of the flagstaff is 60°. What is the height of the flagstaff?
13.5 m
This problem involves trigonometry and geometry to find the height of a vertical flagstaff. We are given the length of a ladder leaning against the flagstaff, the distance from the top of the flagstaff to the point the ladder reaches, and the angle of elevation of the top of the flagstaff from the foot of the ladder.
Let's represent the scenario with a diagram. Assume the ground is horizontal and the flagstaff is vertical.
We have two triangles to consider: the right triangle formed by the foot of the ladder, the foot of the flagstaff, and the point where the ladder touches the flagstaff (\(\triangle\)AFD), and the right triangle formed by the foot of the ladder, the foot of the flagstaff, and the top of the flagstaff (\(\triangle\)AFC).
Now we have a system of two equations:
Substitute the expression for x from equation (2) into equation (1):
\(81 = \left(\frac{h+9}{\sqrt{3}}\right)^2 + h^2\)
Simplify the equation:
\(81 = \frac{(h+9)^2}{3} + h^2\)
Multiply the entire equation by 3 to eliminate the denominator:
\(3 \times 81 = 3 \times \left(\frac{(h+9)^2}{3}\right) + 3 \times h^2\)
\(243 = (h+9)^2 + 3h^2\)
Expand the term \((h+9)^2 = h^2 + 2 \times h \times 9 + 9^2 = h^2 + 18h + 81\):
\(243 = (h^2 + 18h + 81) + 3h^2\)
Combine like terms:
\(243 = 4h^2 + 18h + 81\)
Rearrange into a quadratic equation in the form \(ax^2 + bx + c = 0\):
\(4h^2 + 18h + 81 - 243 = 0\)
\(4h^2 + 18h - 162 = 0\)
Divide the equation by 2 to simplify:
\(2h^2 + 9h - 81 = 0\)
We use the quadratic formula \(h = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) with a=2, b=9, c=-81.
\(h = \frac{-9 \pm \sqrt{9^2 - 4(2)(-81)}}{2(2)}\)
\(h = \frac{-9 \pm \sqrt{81 + 648}}{4}\)
\(h = \frac{-9 \pm \sqrt{729}}{4}\)
Calculate the square root of 729:
\(\sqrt{729} = 27\)
So, the possible values for h are:
\(h_1 = \frac{-9 + 27}{4} = \frac{18}{4} = 4.5\)
\(h_2 = \frac{-9 - 27}{4} = \frac{-36}{4} = -9\)
Since h represents a height, it must be a positive value. Therefore, we discard the negative solution. So, h = 4.5 m.
The total height of the flagstaff (FC) is h + 9.
\(\text{Height of flagstaff} = h + 9 = 4.5 + 9 = 13.5 \text{ m}\)
The height of the flagstaff is 13.5 m.
| Measurement | Value | Notes |
|---|---|---|
| Ladder Length (AD) | 9 m | Given |
| Distance from D to C (DC) | 9 m | Given |
| Angle of Elevation (\(\angle\)FAC) | 60° | Given |
| Height reached by ladder (FD or h) | 4.5 m | Calculated |
| Total Flagstaff Height (FC = FD + DC) | 13.5 m | Calculated |
This problem demonstrates the application of basic trigonometric ratios and the Pythagorean theorem in solving geometric problems involving heights and distances.
Combining these concepts allows us to set up equations relating the knowns and unknowns and solve for the required quantity, the flagstaff height.
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