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Question

A ladder 9 m long reaches a point 9 m below the top of a vertical flagstaff. From the foot of the ladder, the elevation of the flagstaff is 60°. What is the height of the flagstaff?

This question was previously asked in
NDA II 2019 GAT Previous Year Paper (17-Nov-2019)
The correct answer is

13.5 m

Understanding the Flagstaff Height Problem

This problem involves trigonometry and geometry to find the height of a vertical flagstaff. We are given the length of a ladder leaning against the flagstaff, the distance from the top of the flagstaff to the point the ladder reaches, and the angle of elevation of the top of the flagstaff from the foot of the ladder.

Setting up the Geometry

Let's represent the scenario with a diagram. Assume the ground is horizontal and the flagstaff is vertical.

  • Let F be the foot of the flagstaff on the ground.
  • Let C be the top of the flagstaff. So, FC is the total height of the flagstaff.
  • Let A be the foot of the ladder on the ground. Assume A and F are the same point for simplicity, as the angle of elevation is given from the foot of the ladder to the top of the flagstaff. So, A = F. Let's call the foot of the flagstaff and ladder F.
  • Let D be the point on the flagstaff where the top of the ladder rests. D is on the line segment FC.
  • The ladder is AD, and its length is given as 9 m. So, AD = 9 m.
  • The point D is 9 m below the top C. So, DC = 9 m.
  • The total height of the flagstaff is FC = FD + DC. Let FD = h. Then FC = h + 9 m.
  • The angle of elevation of the top of the flagstaff (C) from the foot of the ladder (A, which is F) is 60°. So, in the right triangle FRC, \(\angle FAC = \angle FRC = 60^\circ\), where R is the point on the ground directly below the top of the flagstaff. Since F is the foot of the flagstaff, the triangle is FRC, which is a right triangle at F. \(\angle AFC = 60^\circ\). Let FA be the distance from the foot of the ladder to the foot of the flagstaff. In the problem setup, the foot of the ladder is at the same point as the foot of the flagstaff for calculating the angle of elevation. Let's call this common point F. The diagram is a right triangle with vertices F (foot of flagstaff/ladder), F (foot of flagstaff, let's use a different point for the ladder's foot if it's not the same), let's reconsider the wording: "From the foot of the ladder, the elevation of the flagstaff is 60°". This implies the foot of the ladder is a point A, and the foot of the flagstaff is F, with AF being a horizontal distance. The ladder is 9m long and reaches a point D on the flagstaff. Let the foot of the ladder be A, the foot of the flagstaff be F, and the top of the flagstaff be C. The ladder is AD, AD = 9m. D is on FC. DC = 9m. The angle of elevation of C from A is 60°. So, \(\angle FAC = 60^\circ\). In the right triangle AFC, \(\angle AFC = 90^\circ\). Let AF = x and FC = H. Then \(\tan(60^\circ) = \frac{FC}{AF} = \frac{H}{x}\). Also, in the right triangle AFD, \(\angle AFD = 90^\circ\). AD = 9, AF = x. Let FD = h. Then \(H = h + 9\). By Pythagorean theorem in \(\triangle AFD\), \(AD^2 = AF^2 + FD^2\), so \(9^2 = x^2 + h^2\), i.e., \(81 = x^2 + h^2\).

We have two triangles to consider: the right triangle formed by the foot of the ladder, the foot of the flagstaff, and the point where the ladder touches the flagstaff (\(\triangle\)AFD), and the right triangle formed by the foot of the ladder, the foot of the flagstaff, and the top of the flagstaff (\(\triangle\)AFC).

  • In \(\triangle\)AFD: AD = 9 m (ladder length), AF = x (distance from ladder foot to flagstaff foot), FD = h (height reached by ladder). By Pythagoras theorem: \(AD^2 = AF^2 + FD^2 \implies 9^2 = x^2 + h^2 \implies 81 = x^2 + h^2\).
  • In \(\triangle\)AFC: AF = x, FC = H (total flagstaff height), \(\angle FAC = 60^\circ\) (angle of elevation). FC = FD + DC = h + 9. Using trigonometry (\(\tan\)): \(\tan(60^\circ) = \frac{FC}{AF} \implies \sqrt{3} = \frac{h+9}{x} \implies x = \frac{h+9}{\sqrt{3}}\).

Solving the Equations

Now we have a system of two equations:

  1. \(81 = x^2 + h^2\)
  2. \(x = \frac{h+9}{\sqrt{3}}\)

Substitute the expression for x from equation (2) into equation (1):

\(81 = \left(\frac{h+9}{\sqrt{3}}\right)^2 + h^2\)

Simplify the equation:

\(81 = \frac{(h+9)^2}{3} + h^2\)

Multiply the entire equation by 3 to eliminate the denominator:

\(3 \times 81 = 3 \times \left(\frac{(h+9)^2}{3}\right) + 3 \times h^2\)

\(243 = (h+9)^2 + 3h^2\)

Expand the term \((h+9)^2 = h^2 + 2 \times h \times 9 + 9^2 = h^2 + 18h + 81\):

\(243 = (h^2 + 18h + 81) + 3h^2\)

Combine like terms:

\(243 = 4h^2 + 18h + 81\)

Rearrange into a quadratic equation in the form \(ax^2 + bx + c = 0\):

\(4h^2 + 18h + 81 - 243 = 0\)

\(4h^2 + 18h - 162 = 0\)

Divide the equation by 2 to simplify:

\(2h^2 + 9h - 81 = 0\)

Solving the Quadratic Equation for h

We use the quadratic formula \(h = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) with a=2, b=9, c=-81.

\(h = \frac{-9 \pm \sqrt{9^2 - 4(2)(-81)}}{2(2)}\)

\(h = \frac{-9 \pm \sqrt{81 + 648}}{4}\)

\(h = \frac{-9 \pm \sqrt{729}}{4}\)

Calculate the square root of 729:

\(\sqrt{729} = 27\)

So, the possible values for h are:

\(h_1 = \frac{-9 + 27}{4} = \frac{18}{4} = 4.5\)

\(h_2 = \frac{-9 - 27}{4} = \frac{-36}{4} = -9\)

Since h represents a height, it must be a positive value. Therefore, we discard the negative solution. So, h = 4.5 m.

Calculating the Total Flagstaff Height

The total height of the flagstaff (FC) is h + 9.

\(\text{Height of flagstaff} = h + 9 = 4.5 + 9 = 13.5 \text{ m}\)

Conclusion on Flagstaff Height

The height of the flagstaff is 13.5 m.

Revision Table: Flagstaff Height Calculation

Measurement Value Notes
Ladder Length (AD) 9 m Given
Distance from D to C (DC) 9 m Given
Angle of Elevation (\(\angle\)FAC) 60° Given
Height reached by ladder (FD or h) 4.5 m Calculated
Total Flagstaff Height (FC = FD + DC) 13.5 m Calculated

Additional Information: Trigonometry and Pythagoras

This problem demonstrates the application of basic trigonometric ratios and the Pythagorean theorem in solving geometric problems involving heights and distances.

  • Trigonometric Ratios: In a right-angled triangle, the ratios of the sides are related to the angles. The tangent of an angle (\(\tan \theta\)) is defined as the ratio of the length of the opposite side to the length of the adjacent side. Here, \(\tan(60^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{FC}{AF}\).
  • Pythagorean Theorem: In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides (legs). In \(\triangle\)AFD, \(AD^2 = AF^2 + FD^2\).
  • Angle of Elevation: The angle of elevation is the angle between the horizontal line from the observer's eye to an object and the line of sight to the object, when the object is above the horizontal line.

Combining these concepts allows us to set up equations relating the knowns and unknowns and solve for the required quantity, the flagstaff height.

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Similar Questions

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Important Questions from Heights and Distances

  1. A peacock sitting at the top of a 3 meter high pole saw a snake approaching towards pole at a distance three times of the height of the pole. Then it jumping from pole will catch the snake at what distance from the pole if both are running with same speed ?

  2. The foot of a ladder 25 m long is 7 m from the base of the building. If the top of the ladder slips by 4 m, then by how much distance will the foot of the ladder slide?

  3. Two hotels stand 25 m apart. One of them is 70 m high and the angle of depression of the top of other as observed from the top of this hotel is 45°. Height of the other hotel is:

  4. If the angles of elevation of a balloon from two consecutive kilometer-stones along a straight road are 30° and 60° respectively, then the height of the balloon above the ground will be:

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