From a 50 m long steel bar, a workman has to cut off as many 5.25 m long pieces as possible. What decimal fraction of the whole will be left?
0.055
This problem asks us to find the decimal fraction of a steel bar that is left over after cutting multiple pieces of a specific length. We start with a total length of the steel bar and need to determine how many pieces can be cut and what length remains.
Here’s how we can solve this steel bar cutting problem:
Total length = \(50 \, \text{m}\)
Length per piece = \(5.25 \, \text{m}\)
Number of pieces = \(\frac{\text{Total length}}{\text{Length per piece}} = \frac{50}{5.25}\)
Let's perform the division:
\(\frac{50}{5.25} = \frac{50 \times 100}{5.25 \times 100} = \frac{5000}{525}\)
Now, simplify the fraction:
\(\frac{5000}{525} = \frac{1000 \times 5}{105 \times 5} = \frac{1000}{105}\)
\(\frac{1000}{105} = \frac{200 \times 5}{21 \times 5} = \frac{200}{21}\)
Dividing 200 by 21:
\(200 \div 21 \approx 9.52\)
Since only whole pieces can be cut, the workman can cut 9 pieces.
Number of pieces = 9
Length per piece = \(5.25 \, \text{m}\)
Total length used = \(9 \times 5.25 \, \text{m}\)
\(9 \times 5.25 = 9 \times (5 + 0.25) = (9 \times 5) + (9 \times 0.25) = 45 + 2.25 = 47.25 \, \text{m}\)
The total length used is 47.25 m.
Original total length = \(50 \, \text{m}\)
Total length used = \(47.25 \, \text{m}\)
Length left = \(50 \, \text{m} - 47.25 \, \text{m} = 2.75 \, \text{m}\)
The length of the bar left is 2.75 m.
Length left = \(2.75 \, \text{m}\)
Original total length = \(50 \, \text{m}\)
Decimal fraction left = \(\frac{\text{Length left}}{\text{Original total length}} = \frac{2.75}{50}\)
To convert this fraction to a decimal, we can multiply the numerator and denominator by 2 to make the denominator 100:
\(\frac{2.75}{50} = \frac{2.75 \times 2}{50 \times 2} = \frac{5.5}{100} = 0.055\)
The decimal fraction of the whole bar left is 0.055.
After cutting as many 5.25 m pieces as possible from the 50 m steel bar, the length remaining is 2.75 m. When expressed as a decimal fraction of the original length, this leftover piece is 0.055 of the whole bar.
| Description | Value | Unit |
|---|---|---|
| Original Bar Length | 50 | m |
| Length per Piece | 5.25 | m |
| Maximum Number of Pieces Cut | 9 | - |
| Total Length Used | 47.25 | m |
| Length Left | 2.75 | m |
| Decimal Fraction Left | 0.055 | - |
A decimal fraction is a fraction where the denominator is a power of ten (like 10, 100, 1000, etc.). However, the term is also commonly used to refer to any number written in decimal form, especially when it represents a part of a whole. In this problem, the decimal fraction represents the proportion of the original steel bar that remains after cutting. Calculating this involves division and understanding how to represent quantities as parts of a whole.
When dealing with real-world problems like steel bar cutting, it's important to consider practical constraints, such as only being able to cut whole pieces. This often means using integer division (finding the quotient) to determine the number of items that can be made or cut, before calculating the remainder or leftover quantity.
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