We are given the equation $(\frac{p}{q})^{\frac{p}{q}} = p^{(\frac{p}{q}-1)}$ where $p$ and $q$ are positive integers and $\frac{p}{q} \neq 1$. We need to find the relationship between $p$ and $q$. Let's simplify the equation using logarithms.
Take the natural logarithm (ln) of both sides of the equation:
$\ln\left((\frac{p}{q})^{\frac{p}{q}}\right) = \ln\left(p^{(\frac{p}{q}-1)}\right)$Apply the power rule of logarithms, $\ln(a^b) = b \ln(a)$, to both sides:
$\frac{p}{q} \ln(\frac{p}{q}) = (\frac{p}{q}-1) \ln(p)$Now, apply the quotient rule of logarithms, $\ln(\frac{a}{b}) = \ln(a) - \ln(b)$, to the left side:
$\frac{p}{q} (\ln(p) - \ln(q)) = (\frac{p}{q}-1) \ln(p)$Distribute the terms:
$\frac{p}{q} \ln(p) - \frac{p}{q} \ln(q) = \frac{p}{q} \ln(p) - \ln(p)$Subtract $\frac{p}{q} \ln(p)$ from both sides:
$- \frac{p}{q} \ln(q) = - \ln(p)$Multiply both sides by -1:
$\frac{p}{q} \ln(q) = \ln(p)$Multiply both sides by $q$:
$p \ln(q) = q \ln(p)$Use the power rule of logarithms ($b \ln(a) = \ln(a^b)$) in reverse:
$\ln(q^p) = \ln(p^q)$Since the natural logarithm function is one-to-one, if $\ln(x) = \ln(y)$, then $x=y$. Therefore:
$q^p = p^q$This relationship matches Option 1.
If a real variable $x$ satisfies $3^{x^2} = 27 \times 9^x$, then the value of $\frac{2^{x^2}}{(2^{x})^2}$ is:
The 12 musical notes are given as C, C#, D, D#, E, F, F#, G, G#, A, A#. Frequency of each note is $ \sqrt[12]{2} $ times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is: