For any two independent events A and B, P(A - B) is equal to:
P(A) - P(A)P(B)
The question asks for the probability of the event (A - B) when A and B are two independent events. The event (A - B) represents the outcomes where event A occurs, but event B does not occur. This is also known as the set difference between A and B, and can be written as A $\cap$ B', where B' is the complement of event B.
For any two events A and B, the probability of the event (A - B) can be expressed using the formula related to intersections:
$$P(A - B) = P(A \cap B')$$
Alternatively, the probability of A occurring but B not occurring can be found by subtracting the probability of both A and B occurring from the probability of A occurring. This is because A can be partitioned into two disjoint events: (A $\cap$ B) and (A $\cap$ B').
So, we have:
$$P(A) = P(A \cap B) + P(A \cap B')$$
Rearranging this formula to find $P(A \cap B')$:
$$P(A \cap B') = P(A) - P(A \cap B)$$
Therefore, the probability of A - B is given by:
$$P(A - B) = P(A) - P(A \cap B)$$
The question states that events A and B are independent. This is a crucial piece of information. The definition of independence between two events A and B is that the occurrence of one event does not affect the probability of the occurrence of the other event.
Mathematically, for independent events A and B, the probability of their intersection (both A and B occurring) is equal to the product of their individual probabilities:
$$P(A \cap B) = P(A) \times P(B)$$
Now we can substitute the property of independent events into the formula for $P(A - B)$:
We have the formula: $P(A - B) = P(A) - P(A \cap B)$
Substitute $P(A \cap B) = P(A)P(B)$ because A and B are independent:
$$P(A - B) = P(A) - P(A)P(B)$$
This expression gives the probability of event A occurring but event B not occurring, given that A and B are independent.
Let's compare our derived formula with the given options:
Our derived result, $P(A) - P(A)P(B)$, matches Option 1.
Let's briefly consider why other options are generally incorrect for independent events A and B:
Therefore, for independent events A and B, $P(A - B)$ is indeed equal to $P(A) - P(A)P(B)$.
| Concept | Notation | Formula (General) | Formula (Independent A, B) |
|---|---|---|---|
| Probability of A and B (Intersection) | P(A $\cap$ B) or P(AB) | P(A|B)P(B) or P(B|A)P(A) | P(A)P(B) |
| Probability of A or B (Union) | P(A $\cup$ B) | P(A) + P(B) - P(A $\cap$ B) | P(A) + P(B) - P(A)P(B) |
| Probability of A but not B (Set Difference A-B) | P(A - B) or P(A $\cap$ B') | P(A) - P(A $\cap$ B) | P(A) - P(A)P(B) |
| Probability of not A (Complement) | P(A') | 1 - P(A) | 1 - P(A) (Independence doesn't change this) |
It is important not to confuse independent events with mutually exclusive events. These are different concepts in probability.
The formula $P(A - B) = P(A) - P(A \cap B)$ applies to any two events. When the events are independent, we simply replace $P(A \cap B)$ with $P(A)P(B)$ to get the specific formula for independent events.
The first four raw moments of distribution are 2, 136, 320, and 40,000, The coefficient of skewness is:
For a distribution, the percentile partition values are P 10 = 58.983, P 50 = 61.345 and P 90 = 63.831. Kelly's coefficient of skewness is:
A box contains four soccer balls printed with numbers 112, 121, 211. 222. A footballer chooses one ball at random. Let A 1be the event that the first digit of the printed number of the ball chosen is 1. Similarly, A 2and A 3denote that second as well as third digit of the printed number is 1. The events A 1,A 2, and A 3are:
If the Bowley’s coefficient of skewness is less than zero, then the distribution is:
If μ 4, = 199, μ 3= 50 and μ 2= 8, then the value of excess kurtosis is:
If the data are skewed, which option of central tendency measure is the most unreliable indicator?
A and B are two events. A and B are their complement events, respectively, such that AB and AB are two mutually exclusive and exhaustive events in which the event A can occur. Then which option is correct?
If the distribution is negatively skewed, then the:
The first four moments about the mean of distribution are 0, μ 2, 0.7 and 18.75. If the distribution is mesokurtic, the value of μ 2, is
The following measures were computed for a moderately symmetrical frequency distribution: mean = 50, coefficient of variation = 35% and Karl Pearson's Coefficient of Skewness = - 0.25. The value of the median of the distribution is:
Events A, Band C are mutually exclusive events such that \(P(A) = \dfrac{3x + 1}{3}, P(B) = \dfrac{1-x}{4}\)and \(P(C) = \dfrac{1-2x}{4}\)The set of possible values of x are in the interval
Let A, B be two events in a discrete probability space with ℙ(A) > 0 and ℙ(B) > 0. Which of the following are necessarily true?
A box contains 2 washers, 3 nuts and 4 bolts. Items are drawn from the box at random one at a time without replacement. The probability of drawing 2 washers first followed by 3 nuts and subsequently the 4 bolts is