For a sample data, mean = 60 and median = 48. For this distribution, the mode is:
24
In statistics, the mean, median, and mode are important measures of central tendency. They help us understand the typical value in a dataset. For some distributions, especially those that are not symmetrical, there is a relationship between these three measures.
For a moderately skewed distribution, there is an empirical relationship that connects the mean, median, and mode. This relationship is given by the formula:
\(\text{Mode} \approx 3 \times \text{Median} - 2 \times \text{Mean}\)
This formula is useful when you know two of the measures and need to estimate the third, particularly in distributions that are not perfectly symmetrical but not extremely skewed either.
We are given the following information for a sample data distribution:
We can use the empirical formula to estimate the mode for this distribution.
Substitute the given values into the formula:
\(\text{Mode} \approx 3 \times \text{Median} - 2 \times \text{Mean}\)
\(\text{Mode} \approx 3 \times 48 - 2 \times 60\)
First, perform the multiplications:
\(3 \times 48 = 144\)
\(2 \times 60 = 120\)
Now, substitute these results back into the formula:
\(\text{Mode} \approx 144 - 120\)
Finally, perform the subtraction:
\(\text{Mode} \approx 24\)
Using the empirical formula for a moderately skewed distribution, the estimated mode for the sample data with a mean of 60 and a median of 48 is 24.
It's important to remember that the formula \( \text{Mode} \approx 3 \times \text{Median} - 2 \times \text{Mean} \) is an approximation. It works well for distributions that are unimodal (have one mode) and moderately skewed. It may not be accurate for highly skewed distributions or multi-modal distributions.
| Measure | Description | Affected by Outliers |
|---|---|---|
| Mean | Average value | Yes |
| Median | Middle value when ordered | No |
| Mode | Most frequent value | No (usually) |
The relationship between the mean, median, and mode gives us clues about the shape of a distribution:
In this problem, Mean (60) > Median (48). This suggests the distribution is likely positively skewed, which aligns with the empirical formula resulting in a mode (24) that is the smallest of the three measures.
The given table represents the monthly income of 100 families of a locality.
Monthly income range (in Rs.) | Number of families |
Income more than Rs. 10,000 | 100 |
Income more than Rs. 13,000 | 85 |
Income more than Rs. 16,000 | 69 |
Income more than Rs. 19,000 | 50 |
Income more than Rs. 22,000 | 33 |
Income more than Rs. 25,000 | 15 |
The number of families having income range (in Rs.) 19000 - 22000 is:
Find the mode for the given distribution (rounded off to two decimal places).
| Class Interval | 5-10 | 10-15 | 15-20 | 20-25 | 25-30 | 30-35 |
| Frequency | 8 | 7 | 6 | 9 | 11 | 10 |
The arithmetic mean of the following data is _________.
23, 17, 20, 19, 21
The median of the following data will be _________.
32, 25, 33, 27, 35, 29 and 30
The mode of the following data is __________.
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Source of Variations | SS | Df | MSS | F-Ratio |
Variety A | 280 | 2 | 140 | 42.04 |
Variety B | α | 3 | 34.03 | |
Error | 20 | β | 3.33 | |
Total | 640 | 11 |
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Saving (In Rs.) | Number of people |
5 | 1 |
15 | 3 |
20 | 4 |
25 | 2 |
30 | 1 |
35 | 1 |
40 | 2 |
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