The data given below shows the number of people who have saved a certain amount of money. Saving (In Rs.) Number of people 5 1 15 3 20 4 25 2 30 1 35 1 40 2 What is the median of the given data?
Rs. 20
The question provides data showing the amount of money saved by a certain number of people. This is a frequency distribution for discrete data. To find the median of this data, we need to determine the middle value when all the savings amounts are arranged in ascending order.
The data is presented as pairs of Savings amount and the number of people who saved that amount (frequency).
| Saving (In Rs.) | Number of people (Frequency, \(f\)) |
|---|---|
| 5 | 1 |
| 15 | 5 |
| 20 | 3 |
| 25 | 2 |
| 30 | 3 |
| 35 | 1 |
| 40 | 2 |
The total number of people is the sum of the frequencies.
Total number of people \(N = \sum f\).
\(N = 1 + 5 + 3 + 2 + 3 + 1 + 2 = 17\)
So, there are 17 observations in total.
For a dataset with an odd number of observations \(N\), the median is the value at the \(\frac{N+1}{2}\)th position when the data is arranged in ascending order.
Median position = \(\frac{17+1}{2} = \frac{18}{2} = 9\)th term.
We need to find the savings amount corresponding to the 9th person when listed by their savings in ascending order.
To find which savings amount corresponds to the 9th term, we calculate the cumulative frequency. Cumulative frequency (CF) for a particular savings amount is the total number of people who saved that amount or less.
| Saving (In Rs.) | Frequency (\(f\)) | Cumulative Frequency (CF) |
|---|---|---|
| 5 | 1 | 1 (1 person saved Rs. 5 or less) |
| 15 | 5 | 1 + 5 = 6 (6 people saved Rs. 15 or less) |
| 20 | 3 | 6 + 3 = 9 (9 people saved Rs. 20 or less) |
| 25 | 2 | 9 + 2 = 11 (11 people saved Rs. 25 or less) |
| 30 | 3 | 11 + 3 = 14 (14 people saved Rs. 30 or less) |
| 35 | 1 | 14 + 1 = 15 (15 people saved Rs. 35 or less) |
| 40 | 2 | 15 + 2 = 17 (17 people saved Rs. 40 or less) |
We are looking for the 9th term. We check the cumulative frequency column.
Since the cumulative frequency becomes 9 at the saving amount of Rs. 20, the 9th term is Rs. 20.
Therefore, the median of the given data is Rs. 20.
| Concept | Description | Applicability |
|---|---|---|
| Median | The middle value of a dataset when ordered. | All types of data (quantitative) |
| Frequency (\(f\)) | Number of times a value appears. | Grouped or frequency data |
| Cumulative Frequency (CF) | Sum of frequencies up to a certain value. | Finding median/quartiles in frequency distributions |
| Median Position (Odd N) | \(\frac{N+1}{2}\)th term | Dataset with an odd number of observations |
| Median Position (Even N) | Average of \(\frac{N}{2}\)th and \((\frac{N}{2}+1)\)th terms | Dataset with an even number of observations |
Measures of central tendency are single values that describe the center point of a data set. The three main measures are:
Choosing the appropriate measure depends on the type of data and the presence of outliers. For data with extreme values, the median is often a better measure of central tendency than the mean.
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Given below is the marks obtained by 20 students in mathematics out of 30 marks.
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