For a quarter wave ideal transmission line of characteristic impedance of 50 Ω and load impedance of 100 Ω, the input impedance of line will be :
25 Ω
The quarter-wave transformer relation. Starting from the general lossless line equation
\(Z_{in}=Z_0\dfrac{Z_L+jZ_0\tan\beta l}{Z_0+jZ_L\tan\beta l}\)
and putting \(l=\lambda/4\), so that \(\beta l=\pi/2\) and \(\tan\beta l\to\infty\), the terms without the tangent become negligible and
\(Z_{in}=\dfrac{Z_0^{2}}{Z_L}\)
Step — substitute.
\(Z_{in}=\dfrac{50^{2}}{100}=\dfrac{2500}{100}=25\ \Omega\)
which is option 2.
The property that makes this memorable. A quarter-wave line is an impedance inverter: it reflects the load about Z0 on a logarithmic scale. Here the load is twice the characteristic impedance and the input comes out half of it. Rearranging,
\(Z_0=\sqrt{Z_{in}Z_L}\)
so Z0 is the geometric mean of the two ends — check: \(\sqrt{25\times100}=50\) ✓.
The two extreme cases worth carrying.
| Load | Zin of a λ/4 line |
|---|---|
| Short circuit, ZL = 0 | Open circuit, ∞ |
| Open circuit, ZL = ∞ | Short circuit, 0 |
| Matched, ZL = Z0 | Z0 — unchanged |
That first row is the basis of the quarter-wave stub, used as a mechanical support that is electrically invisible, and of the λ/4 choke in coaxial connectors.
Why it matters in practice. Read backwards, the geometric-mean relation is a matching recipe: to feed a 100 Ω antenna from a 50 Ω cable, insert a quarter-wave section of
\(Z_0=\sqrt{50\times100}=70.7\ \Omega\)
which is exactly why 75 Ω cable is stocked alongside 50 Ω. The one limitation is that the length is a quarter wavelength at a single frequency, so the match is inherently narrowband; multi-section transformers are used to widen it.
Where the distractors come from. 100 Ω is the load itself, which would be the answer for a half-wave line; 50 Ω would require the load to equal Z0; 175 Ω corresponds to no standard relation.
Hence, the input impedance is 25 Ω.
Consider the following statements
A. Reflection coefficient is change in the magnitude of reflected wave with constant phase with respect to incident wave.
B. Transmission coefficient is change in the magnitude and phase of transmitted wave with respect to incident wave
C. On smith chart, \(\dfrac{\lambda}{2}\) distance is equivalent to 2π.
D. For distortion less line, RL = GC
E. Directivity of an antenna can be less than 1 (unity).
Choose the most appropriate answer from the options given below :
In a loss less transmission line of length 50 cm with L = 10 μH/m, C = 40 pF/m is operated at 25 MHz. Its electrical path length is
The normalized impedance of a transmission line is given by expression :
A lossless line has a characteristic impedance of 50 ohms. It is terminated in a load resistance of 75 ohms. The line is energised by a generator which has an output impedance of 50 ohms and an output voltage of 30 V (rms). The line is assumed to be 2.25 wavelength long. The input impedance and instantaneous load voltages are given :
(a) Zin = 50 ohms (b) VL (instantaneous) = 36 V (c) Zin = 33.33 ohms (d) VL (instantaneous) = 12 V
Which of the above are correct :
Arrange the below mentioned transmission lines in order of their increasing frequency handling capabilities :
(a) wave guide (b) Parallel wire (c) Rigid co-axial cables (d) Flexible co-axial cables
The disadvantage of co-axial cable is/are :
(A) Support higher bandwidth than twisted pair cable
(B) Light weight
(C) Relatively expensive compared to twisted pair cable
(D) EMI resistant
(E) Doesn't at very high frequency
Choose the most appropriate answer from the options given below :
The propagation constant for uniform plane wave is given by the expression given below :
A characteristic impedance does NOT satisfy which of the following statements?
The dielectric constant of the material used in a transmission line is 2. What is the velocity factor of this line if its characteristic impedance is 300 Ω?
A transmission line of \(50{\rm{\;\Omega }}\) characteristic impedance is terminated with a \(\rm 100 \ Ω\) resistance. The minimum impedance measured on the line is equal to
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