25 + 26 + .... + 75 = ?
The problem asks for the sum of the series 25 + 26 + ... + 75. This is an arithmetic progression.
Use the formula for the $n$-th term of an arithmetic progression: $l = a + (n-1)d$.
Substitute the known values:
$75 = 25 + (n-1) \times 1$
Solve for $n$:
$75 - 25 = n - 1$
$50 = n - 1$
$n = 50 + 1 = 51$
There are 51 terms in the series.
Use the formula for the sum of an arithmetic progression: $S_n = \frac{n}{2}(a + l)$.
Substitute the values of $n$, $a$, and $l$:
$S_{51} = \frac{51}{2}(25 + 75)$
$S_{51} = \frac{51}{2}(100)$
$S_{51} = 51 \times 50$
$S_{51} = 2550$
The sum of the series is 2550.
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