Find the slope of the line joining the points (3, -4) and (5, 2).
3
The slope of the line joining (x₁, y₁) and (x₂, y₂) is m = (y₂ - y₁)/(x₂ - x₁).
Substituting the points (3, -4) and (5, 2): m = (2 - (-4))/(5 - 3)
= (2 + 4)/2
= 6/2
= 3
Check: from (3, -4) moving 2 units right and 6 units up reaches (5, 2), so rise/run = 6/2 = 3.
Hence, 3.
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Important Questions from Co-ordinate Geometry
In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
In which quadrant both abscissa and ordinate are negative?
Find the slope of the line joining the points (3, -4) and (5, 2).
A1 (x1, y1), A2 (x2, y2), A3 (x3, y3) and A4 (x4, y4) are 4 points, p1 divides A1A2 in the ratio 1 ∶ 1, p2 divides P1A3 in the ratio 1 ∶ 2, P3 divides p2A4 in the ratio 1 ∶ 3. Then the coordinates of p3 are:
If (3, 2) are coordinates of the centroid of a triangle, whose vertices are (0, 4), (-2, 0) and (p, 2), then find the value of p.
