Find the simple interest on ₹ 6,400 at 9% per annum for 3 years.
₹ 1,728
Simple interest is calculated using the formula \(SI = \frac{P \times R \times T}{100}\), where P is the principal, R is the rate of interest, and T is the time in years.
Substituting P = 6400, R = 9, and T = 3:
\(SI = \frac{6400 \times 9 \times 3}{100} = 1728\)
Hence, the simple interest is ₹1,728.
A sum of ₹7,500 is invested at 8% per annum simple interest. After 3 years, the amount obtained is reinvested for 2 more years at the same rate. Find the final amount.
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A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?