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Question

Find the odd word/letter/number/pair from the given alternatives

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

M N O M

To determine the odd word/letter/number/pair from the given alternatives, we need to analyze the structure of each option. Each option consists of sequences of letters with a repeated pattern.

1. M N O M: This sequence does not follow a consistent alphabetical order. Instead, 'M' is repeated at the beginning and end, while 'N' and 'O' are in between.

2. B D C B: Starting with 'B', followed by 'D', then 'C', and repeating 'B'. Observing positions: B(2), D(4), C(3), B(2); notice the alphabetical order isn't consistent.

3. X Z Y X: This sequence starts with 'X', followed by 'Z', then 'Y', and ends with 'X'. The alphabetic positions are X(24), Z(26), Y(25), X(24). The first and last letters repeat, Z and Y are in decreasing order.

4. P R Q P: Begins with 'P', followed by 'R', then 'Q', and repeats 'P'. The positions are P(16), R(18), Q(17), P(16); there's a decreasing sequence between 'R' and 'Q'.

Upon analyzing each sequence, we notice a unique pattern in option M N O M. The order M(13), N(14), O(15), M(13) increases and repeats 'M', whereas other options have alternating orders in the middle letters. Therefore, M N O M is the odd sequence out.

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