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Question

Find the coordinates of the points where the graph 57x - 19y = 399 cuts the coordinate axes.

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

x-axis at (7, 0) and y-axis at (0, -21)

Finding Graph Intercepts on Coordinate Axes

The question asks us to find the points where the graph of the linear equation $\text{57x - 19y = 399}$ intersects the coordinate axes. The coordinate axes are the x-axis and the y-axis.

A point where a graph intersects the x-axis is called the x-intercept. At any point on the x-axis, the y-coordinate is always 0.

A point where a graph intersects the y-axis is called the y-intercept. At any point on the y-axis, the x-coordinate is always 0.

Calculating the X-intercept

To find the x-intercept, we set $\text{y = 0}$ in the given equation and solve for $\text{x}$.

The equation is: $\text{57x - 19y = 399}$

Substitute $\text{y = 0}$:

$\text{57x - 19(0) = 399}$

$\text{57x - 0 = 399}$

$\text{57x = 399}$

Now, solve for $\text{x}$ by dividing both sides by 57:

$\text{x = } \frac{399}{57}$

We can perform the division:

Calculation Step Value
$\text{399} \div \text{57}$ $\text{7}$

So, $\text{x = 7}$.

The x-intercept occurs when $\text{x = 7}$ and $\text{y = 0}$. The coordinates of the x-intercept are $(\text{7, 0})$.

Calculating the Y-intercept

To find the y-intercept, we set $\text{x = 0}$ in the given equation and solve for $\text{y}$.

The equation is: $\text{57x - 19y = 399}$

Substitute $\text{x = 0}$:

$\text{57(0) - 19y = 399}$

$\text{0 - 19y = 399}$

$\text{-19y = 399}$

Now, solve for $\text{y}$ by dividing both sides by -19:

$\text{y = } \frac{399}{-19}$

We can perform the division:

Calculation Step Value
$\text{399} \div \text{19}$ $\text{21}$
$\frac{399}{-19}$ $\text{-21}$

So, $\text{y = -21}$.

The y-intercept occurs when $\text{x = 0}$ and $\text{y = -21}$. The coordinates of the y-intercept are $(\text{0, -21})$.

Summary of Intercepts

The graph of the equation $\text{57x - 19y = 399}$ cuts the coordinate axes at the following points:

  • On the x-axis: $(\text{7, 0})$
  • On the y-axis: $(\text{0, -21})$

Comparing these results with the given options, we find that the graph cuts the x-axis at $(\text{7, 0})$ and the y-axis at $(\text{0, -21})$.

Revision Table: Graph Intercepts

Concept Definition How to Find
X-intercept The point(s) where a graph crosses the x-axis. Set $\text{y = 0}$ in the equation and solve for $\text{x}$.
Y-intercept The point(s) where a graph crosses the y-axis. Set $\text{x = 0}$ in the equation and solve for $\text{y}$.
Coordinate Axes The perpendicular lines (x-axis and y-axis) used to define coordinates in a 2D plane. -

Additional Information: Linear Equation Graphs

A linear equation in two variables, like $\text{57x - 19y = 399}$, represents a straight line when graphed on a coordinate plane.

  • The general form of a linear equation is $\text{Ax + By = C}$, where A, B, and C are constants, and A and B are not both zero.
  • In our equation, $\text{A = 57}$, $\text{B = -19}$, and $\text{C = 399}$.
  • The intercepts are often useful points for quickly sketching the graph of a linear equation. Once you have the two intercepts, you can draw a straight line through them.
  • Every point $(\text{x, y})$ that lies on the line satisfies the equation.
  • A non-vertical line (like this one) will have exactly one x-intercept and exactly one y-intercept, unless it passes through the origin (0,0), in which case both intercepts are (0,0).
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Important Questions from General Equation of a Line

  1. Two straight lines passing through the point A(3, 2) cut the line 2y = x + 3 and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

  2. Lines x = ay + b, z = cy + d

    and x = a'y + b', z = c'y + d'

    are perpendicular, if

  3. Equation of the line perpendicular to x - 2y = 1 and passing through (1, 1) is:

  4. If (2, 1), (–1, –2), (3, 3) are the midpoints of the sides BC, CA, AB of a triangle ABC, then equation of the line BC is

  5. Find the equation of a straight line passing through (3, 4) and having slope 3.

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