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Question

Equation of the line perpendicular to x - 2y = 1 and passing through (1, 1) is:

The correct answer is

y = -2x + 3

Finding the Perpendicular Line Equation

The problem asks us to find the equation of a line that satisfies two conditions: it must be perpendicular to the line given by the equation $x - 2y = 1$, and it must pass through the point $(1, 1)$. We can solve this by first determining the slope of the given line, then finding the slope of the perpendicular line, and finally using the point-slope form to find the equation.

Step 1: Determine the Slope of the Given Line

The equation of the given line is $x - 2y = 1$. To find its slope, we need to rewrite this equation in the slope-intercept form, which is $y = mx + c$, where '$m$' represents the slope and '$c$' represents the y-intercept.

Rearranging the equation:

  • Subtract '$x$' from both sides: $-2y = -x + 1$
  • Divide both sides by $-2$: $y = \frac{-x}{-2} + \frac{1}{-2}$
  • Simplify: $y = \frac{1}{2}x - \frac{1}{2}$

From this slope-intercept form, we can see that the slope of the given line ($m_1$) is $\frac{1}{2}$.

Step 2: Calculate the Slope of the Perpendicular Line

Two lines are perpendicular if the product of their slopes is $-1$. Let the slope of the required perpendicular line be $m_2$. Therefore, the relationship between the slopes is:

$$ m_1 \times m_2 = -1 $$

Substitute the slope of the given line ($m_1 = \frac{1}{2}$):

$$ \frac{1}{2} \times m_2 = -1 $$

To find $m_2$, multiply both sides by $2$:

$$ m_2 = -1 \times 2 $$

$$ m_2 = -2 $$

So, the slope of the line perpendicular to the given line is $-2$.

Step 3: Use the Point-Slope Form to Find the Equation

We have the slope of the required line ($m = -2$) and a point it passes through ($(x_1, y_1) = (1, 1)$). We can use the point-slope form of a linear equation, which is $y - y_1 = m(x - x_1)$.

Substitute the values:

$$ y - 1 = -2(x - 1) $$

Now, simplify the equation:

  • Distribute the $-2$ on the right side: $y - 1 = -2x + 2$
  • Add $1$ to both sides to isolate '$y$': $y = -2x + 2 + 1$
  • Combine the constants: $y = -2x + 3$

Step 4: Compare with the Given Options

The equation we derived is $y = -2x + 3$. Let's compare this with the given options:

  • Option 1: $x + 2y = 3 \implies y = -\frac{1}{2}x + \frac{3}{2}$
  • Option 2: $x + y = 2 \implies y = -x + 2$
  • Option 3: $y = 2x + 3$
  • Option 4: $y = -2x + 3$

Our calculated equation $y = -2x + 3$ matches Option 4.

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Important Questions from General Equation of a Line

  1. Two straight lines passing through the point A(3, 2) cut the line 2y = x + 3 and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

  2. Lines x = ay + b, z = cy + d

    and x = a'y + b', z = c'y + d'

    are perpendicular, if

  3. If (2, 1), (–1, –2), (3, 3) are the midpoints of the sides BC, CA, AB of a triangle ABC, then equation of the line BC is

  4. Find the equation of a straight line passing through (3, 4) and having slope 3.

  5. If P(3, 4) is the mid-point of a line segment between the axes, then what is the equation of the line?

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