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Question

Find the angle between the hour hand and the minute hand of a clock at 6 ∶ 10

This question was previously asked in
UPSSSC PET 2022 Question Paper (16-Oct-2022) (Shift 2)
The correct answer is 125 °

Finding the Clock Hand Angle at 6:10

This explanation details how to find the angle between the hour hand and the minute hand of a standard analog clock when the time is exactly 6:10.

Understanding Clock Hand Movement

To calculate the angle, we need to know how the clock hands move:

  • The minute hand completes a full circle (360 degrees) in 60 minutes. Therefore, its speed is calculated as: $$ \text{Minute Hand Speed} = \frac{360^\circ}{60 \text{ minutes}} = 6^\circ \text{ per minute} $$
  • The hour hand completes a full circle (360 degrees) in 12 hours. Its base speed is: $$ \text{Hour Hand Speed (per hour)} = \frac{360^\circ}{12 \text{ hours}} = 30^\circ \text{ per hour} $$
  • Additionally, the hour hand moves continuously as the minutes pass. In 60 minutes, the hour hand moves 30 degrees (the distance between two hour marks). So, its speed per minute is: $$ \text{Hour Hand Speed (per minute)} = \frac{30^\circ}{60 \text{ minutes}} = 0.5^\circ \text{ per minute} $$

Calculating Hand Positions at 6:10

We need to determine the exact position (in degrees) of both hands relative to the '12' mark at 6:10.

Minute Hand Position

At 6:10, the minute hand is pointing at the '2' (10 minutes past the hour). We calculate its position using its speed per minute:

  • Position = Minutes past the hour $ \times $ Speed per minute
  • $ \text{Minute Hand Angle} = 10 \text{ min} \times 6^\circ/\text{min} $
  • $ \text{Minute Hand Angle} = 60^\circ $

So, the minute hand is at 60 degrees from the 12 o'clock position.

Hour Hand Position

At 6:10, the hour hand has moved past the '6'. We calculate its position based on the hours and the additional minutes:

  • The position at the exact hour (6) is $ 6 \text{ hours} \times 30^\circ/\text{hour} = 180^\circ $.
  • In addition, we account for the movement during the 10 minutes past 6: $ 10 \text{ min} \times 0.5^\circ/\text{min} = 5^\circ $.
  • Total Position = Position at 6 o'clock + Movement due to minutes
  • $ \text{Hour Hand Angle} = 180^\circ + 5^\circ $
  • $ \text{Hour Hand Angle} = 185^\circ $

Therefore, the hour hand is at 185 degrees from the 12 o'clock position.

Determining the Angle Between Hands

The angle between the two hands is the absolute difference between their positions:

  • $ \text{Angle} = |\text{Hour Hand Angle} - \text{Minute Hand Angle}| $
  • $ \text{Angle} = |185^\circ - 60^\circ| $
  • $ \text{Angle} = |125^\circ| $
  • $ \text{Angle} = 125^\circ $

Since this angle ($125^\circ$) is less than 180 degrees, it is the smaller angle between the hands.

Conclusion

The angle between the hour hand and the minute hand at 6:10 is 125 degrees.

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