If 18 th February, 2005 falls on Friday then what will be the day on 18th February, 2007?
Sunday
This question asks us to determine the day of the week for a future date based on a known past date. We are given that 18th February, 2005, was a Friday, and we need to find the day for 18th February, 2007.
To find the day of the week for the later date, we need to calculate the total number of days between the two given dates (18th February, 2005 and 18th February, 2007) and then determine the number of 'odd days'. An odd day is the remainder left after dividing the total number of days by 7.
The time span is from 18th February, 2005, to 18th February, 2007. This covers exactly 2 years.
We need to check if any leap years occur within this period. A leap year has 366 days, while a normal year has 365 days. A year is typically a leap year if it is divisible by 4.
The period from 18th February, 2005, to 18th February, 2007, does not include a February 29th. Therefore, both years in this span can be treated as normal years regarding the day calculation.
A normal year has 365 days. To find the odd days in a normal year, we calculate the remainder when 365 is divided by 7:
$$ \text{Number of odd days} = \frac{365}{7} $$
$$ 365 = (52 \times 7) + 1 $$
So, a normal year has 1 odd day.
Since we have two normal years between 18th February, 2005, and 18th February, 2007:
Total odd days = 1 + 1 = 2 odd days.
We are given that 18th February, 2005, was a Friday. To find the day on 18th February, 2007, we add the total number of odd days (2) to the starting day (Friday).
Therefore, 18th February, 2007, will fall on a Sunday.
| Start Date | Start Day | End Date | Number of Years | Number of Leap Years in Span | Total Odd Days | End Day |
| 18th Feb 2005 | Friday | 18th Feb 2007 | 2 years | 0 | 2 | Sunday |
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