Leap Year Check for 1812

First, determine if 1812 was a leap year, as this affects the total number of days.

• A year is a leap year if it's divisible by 4 (and not by 100 unless also divisible by 400).
• 1812 is divisible by 4 ($1812 \div 4 = 453$).
• Therefore, 1812 was a leap year.

Total Days Calculation

A leap year has 366 days.

So, the year 1812 had 366 days in total.

Day Shift Calculation

The first day of 1812 (January 1st) was a Wednesday. We need the day for the last day (December 31st), which is the 366th day.

The number of days *after* the first day until the last day is $366 - 1 = 365$ days.

To find the shift in the day of the week, calculate the remainder when the number of days passed is divided by 7:

Shift $= 365 \mod 7$

Performing the division: $365 \div 7 = 52$ with a remainder of 1.

So, $365 \mod 7 = 1$. This means the day of the week advances by 1 day.

Final Day Determination

The starting day was Wednesday.

Add the calculated shift of 1 day:

Wednesday + 1 day = Thursday

The last day of 1812 was a Thursday.