Each of the digits in the number 3147958 is arranged in ascending order from left to right. The position of how many digits will remain unchanged as compared to that in the original number?
One
Arrange the digits of 3147958 in ascending order and compare the two numbers place by place.
Digits: 3, 1, 4, 7, 9, 5, 8. In ascending order: 1, 3, 4, 5, 7, 8, 9 → 1345789.
| Position | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Original | 3 | 1 | 4 | 7 | 9 | 5 | 8 |
| Arranged | 1 | 3 | 4 | 5 | 7 | 8 | 9 |
Only position 3 has the same digit (4) in both numbers; every other position changes. Therefore the position of 1 digit remains unchanged.
Check: comparing pairs 3/1, 1/3, 4/4, 7/5, 9/7, 5/8, 8/9, exactly one pair (4/4) matches, so the count is 1.
Hence, One.
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