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Question

Nitin starts from Point A and drives 12 km towards south. He then takes a left turn, drives 15 km, turns left and drives 14 km. He then takes a left turn and drives 19 km. He takes a final left turn, drives 2 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again? (All turns are 90-degree turns only unless specified.)

The correct answer is

4 km to the east

Take Point A as the origin (0, 0), with east as positive x and north as positive y. Driving 12 km south takes Nitin to (0, –12).

Facing south, a left turn means facing east: 15 km east takes him to (15, –12). Another left turn means facing north: 14 km north takes him to (15, 2).

A left turn from north means facing west: 19 km west takes him to (15 – 19, 2) = (–4, 2). A final left turn from west means facing south: 2 km south takes him to (–4, 0), which is Point P.

LegDirectionDistancePosition after the leg
1South12 km(0, –12)
2East15 km(15, –12)
3North14 km(15, 2)
4West19 km(–4, 2)
5South2 km(–4, 0) = P

Point P is 4 km west of Point A on the same east–west line, so to reach A again Nitin must drive 4 km to the east.

Check: total east–west movement is 15 km east – 19 km west = 4 km west, and total north–south movement is 12 + 2 = 14 km south against 14 km north = 0, so P lies exactly 4 km west of A.

Hence, 4 km to the east.

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Important Questions from Direction and Distance

  1. What is the direction of U with respect to P?

  2. What is the shortest distance between R and T?

  3. If a person walks 3m towards the North from point V, takes a right turn and walks for another 15m, which of the following points would he reach?

  4. In which direction is Amit facing at point F?

  5. What is the distance between the starting point and the end point?

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