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Question

Manoj starts from Point A and drives 14 km towards East. He then takes a right turn, drives 12 km, turns right and drives 17 km. He then takes a right turn and drives 21 km. He takes a final right turn, drives 3 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again? (All turns are 90-degree turns only unless specified.)

This question was previously asked in
RRB Technician 2026 Grade 3 Question Paper (7-Oct-2026) (Shift 3)
The correct answer is

9 km to the South

Place Point A at the origin (0, 0) with East as +x and North as +y. Driving 14 km East takes Manoj to (14, 0).

A right turn while facing East makes him face South; 12 km South takes him to (14, –12). A right turn while facing South makes him face West; 17 km West takes him to (14 – 17, –12) = (–3, –12).

A right turn while facing West makes him face North; 21 km North takes him to (–3, –12 + 21) = (–3, 9). The final right turn while facing North makes him face East; 3 km East takes him to Point P = (0, 9).

Point P is at (0, 9) and Point A is at (0, 0), so P lies exactly 9 km due North of A. To return to A he must drive 9 km towards the South.

Check: net East–West movement = 14 – 17 + 3 = 0 km and net North–South movement = –12 + 21 = 9 km North, so the shortest path back is 9 km in the opposite direction, South.

Hence, 9 km to the South.

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Important Questions from Direction and Distance

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    takes a final right turn, drives 7 km and stops at Point P. How far (shortest distance) and
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